I have googled and looked at SO for a while now and can't seem to figure this out. The only requirement Im trying to meet is to return a properly formatted javascript array that contains the results of the sql statement.
I.E.
Given a query:
SELECT NUMBERS FROM TABLE
And results:
NUMBERS
1
2
3
I would like to eventually get back an array like so
["1","2","3"]
Please help me understand where I am going wrong
Here is my php code
<?php
$mysqli = new mysqli("local.host.com", "user", "pass", "db");
$sql = "SELECT DISTINCT NAME FROM table";
$result = $mysqli->query($sql);
while($row = $result->fetch_array())
{
$rows[] = $row['NAME'];
}
echo(json_encode($rows));
$result->close();
/* close connection */
$mysqli->close();
?>
Here is my javascript:
function GetCards()
{
var cardarray = new Array();
//alert('test');
$.getJSON('getcardlist.php', function(data)
{
for(var i=0;i<data.length;i++)
{
cardarray.push(data[i]);
}
//return cardarray;
});
return cardarray;
}
EDIT:
Little more information, Im trying to setup an autocomplete list for jquery ui, this is my setup for the autocomplete widget.
var list = GetCards();
$( "#name" ).autocomplete({
source: list,
minLength: 2
And this is the error Im getting from chrome console
Uncaught TypeError: Cannot read property 'label' of null
2 Answers 2
GetCards is returning an empty array -- which is what you're passing on to the Autocomplete widget -- and causing the widget to throw up the TypeError exception. To pass on the populated array, move the code that instantiates Autocomplete into your getJSON success callback (I'm not sure you even need to loop through data -- unless you need to actually transform its contents in some way):
$.getJSON( 'getcardlist.php', function( data ) {
$( "#name" ).autocomplete( {
source: data,
minLength: 2
} );
} );
Alternatively, consider using Autocomplete's shorthand for loading directly from the data feed (see passing source as a string). However, this approach may require some additional work on the server-side to filter down the list as the user types -- if you want that behavior.
1 Comment
you have to use $.each to get the data
$.getJSON('getcardlist.php', function(data)
{
$.each(data, function(key, val) {
cardarray.push(val);
});
//return cardarray;
});
label.