Shell script to run jar of any version

Question

How can I make a shell script that will execute a jar file, regardless of its version?

Say I have a file:

my-jar-file-1.0.0-SNAPSHOT-executable.jar

I want a shell script that will do something along the lines of

#!/bin/bash
java -some -other -options -jar my-jar-file-1.0.0-SNAPSHOT-executable.jar

But it should execute any version of it, so

1. my-jar-file-1.0.0-SNAPSHOT-executable.jar

2. my-jar-file-1.1.0-SNAPSHOT-executable.jar

3. my-jar-file-1.0.1-SNAPSHOT-executable.jar

should all be executed by the same script.

How can I do this?

• Miquel: I think you should use soft links. ln -s my-jar-file-1.0.1-SNAPSHOT-executable.jar my-jar-file-1.0.1-executable.jar

Answer 1

If name of jar match pattern my-jar-version.jar:

java -jar `ls my-jar*.jar`

Answer 2

We can also think the other way around, why not give a final name to jar, which will remain constant, and no script modifications will be required.

<plugin>
 <groupId>org.apache.maven.plugins</groupId>
 <artifactId>maven-jar-plugin</artifactId>
 <version>2.2</version>
 <configuration>
 <finalName>myname</finalName>
 <configuration>
</plugin>

And if having the version number mandatory, you can write a script to pattern search for that particular jar. And run it accordingly.

I did a similar job using ant, but the goal was different, hope this helps.

Answer 3

Try this in a bash script:

for jarfile in my-jar-file-*-SNAPSHOT-executable.jar; do
 java -some -other -options -jar $jarfile
 echo "done for: $jarfile"
done