I want to use xml.etree.ElementTree to parse an XHTML document in Python 3. The document contains entities, so I cannot use the default parser settings. I'd like to do something similar to:
with urllib.request.urlopen(BASE_URL) as url:
body = url.read()
parser = ET.XMLParser()
parser.parser.UseForeignDTD(True)
parser.entity.update(entitydefs)
etree = ET.ElementTree()
root = etree.fromstring(body)
But fromstring is a free function in ElementTree. How can I achieve something similar with ElementTree instance?
asked Mar 2, 2013 at 19:04
brabec
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2 Answers 2
Well I encountered same problem. The sample code in the question and the chosen answer might work before, but right now it won't work in my Python 3.3 and Python 3.4 environment.
I finally got it working. Quoted from this Q&A.
Inspired by this post, we can just prepend some XML definition to the incoming raw HTML content, and then ElementTree would work out of box.
This works for both Python 2.6, 2.7, 3.3, 3.4.
import xml.etree.ElementTree as ET
html = '''<html>
<div>Some reasonably well-formed HTML content.</div>
<form action="login">
<input name="foo" value="bar"/>
<input name="username"/><input name="password"/>
<div>It is not unusual to see in an HTML page.</div>
</form></html>'''
magic = '''<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd" [
<!ENTITY nbsp ' '>
]>''' # You can define more entities here, if needed
et = ET.fromstring(magic + html)
answered Feb 24, 2016 at 1:18
RayLuo
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Feed the parser:
with urllib.request.urlopen(BASE_URL) as url:
body = url.read()
parser = ET.XMLParser()
parser.parser.UseForeignDTD(True)
parser.entity.update(entitydefs)
parser.feed(body)
root = parser.close() # this returns you the tree
answered Mar 2, 2013 at 19:07
Pavel Anossov
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1 Comment
RayLuo
Original poster asked for Python 3 solution, but
parser.parser.UseForeignDTD(True) doesn't work in Python 3. How come this answer was chosen as the correct answer?lang-py