split a sum into array javascript

Question

I have created a dice function that trows random dices and sum the value of them.

Now every number from 0-9 is connected to a class, so if i get number 4 it should call class " four" So i created a switch from 0-9 . But when i get a sum more than 9 its give me the default number, since the function dosent know that 11 is actually 2 numbers. I was wonder I its possible to split the numbers and put them into an array so when i pass it to the switch it gets med "one" "one" .

Any ideas ?

var value = total;
 switch(this.value){
 case 1:
 value ="one";
 break
 case 2:
 value ="two";
 break
 case 3:
 value ="three";
 break
 case 4:
 value ="four";
 break
 case 5:
 value ="five";
 break
 case 6:
 value ="six";
 break
 case 7:
 value ="seven";
 break
 case 8:
 value ="eight";
 break
 case 9:
 value ="nine";
 break
 case 0:
 value ="zero";
 break
 default:
 value ="zero" 
 }

• Dymond: well, its more like. When i get the sum 11, I would like to call the switch by class "one" + "one" otherwise i would need a endless combinations of numbers to call every sum.

Answer 1

You could use the string split function for that:

var result = this.value.toString(10).split("").map(function(digit) {
 return ["zero", "one", "two", "three", "four", "five",
 "six", "seven", "eight", "nine"][digit];
});

(Of course you can use a loop instead of map; Check this answer and its comments on how the array thing works)

• Bergi: @Dymond: Ah, wait, you're neither switching on the total nor on the value variable, but on the this.value property.

Answer 2

You can use split() after you transformed your number to a string. Then run through the resulting array and assign your classes.

var total = 11;
var pieces = ("" + total).split( "" );
for( var i=0; i<pieces.length; i++) {
 // your switch in here
}

• Dymond: It almost work :) when i do a console.log the log from pieces is ["3"] ["4"] I need to remove the "" dots. is it possible to just print the numbers separly without the dots and squere bracket
• Sirko: @Dymond Easiest way would be to change the condition in your switch clause to use +this,value instead of just value. Or you change the case statements to use strings instead of numbers.