Javascript RegEx: extract part of an url

Question

 if ((urlStr.indexOf('t='))!=-1)
 {
 var pat = /t=(\d+)m(\d+)s/;
 pat.exec(urlStr);
 alert (RegExp.1ドル);
 alert (RegExp.2ドル);
 }

case 1: http://localhost/proc1/commit.php&t=1m13s Returns 1 and 13 -> Okay

case 2: http://localhost/proc1/commit.php&t=13s Returns blank and blank -> Not okay
Expected Result 0 and 13

How do I have to change my regex?

Answer 1

You could try this:

var pat = /t=(?:(\d+)m)?(\d+)s/;

This allows for the first part, including the m to be optional. Now in your second case, 1ドル should be an empty string.

The (?: makes sure, that you do not get another captured string containing the m.

This will work, too, and do pretty much the same:

var pat = /t=(\d*?)m?(\d+)s/;

Here we just allow the first string of digits to be empty, and m to be optional. Just make sure to use ? after the * to make the repetition ungreedy - otherwise the 1 will be matched by the first repetition, m will be left out, and the 3 will be matched by the second repetition.