How to render a view file as json object in symfony2 for ajax requests

Question

I have an action for login process. Now I want to use the same action for normal login process and for ajax requests also.

 /**
 * @Route("/sponsor/login", name="sponsor_login", options={"expose"=true})
 * @Template("SponsorBundle::login.html.twig")
 * @return array
 */
 public function loginAction()
 {}

I want this action to render different view files for xmlhttp request and for normal http request.How do i do that? and I want to pass view file in a json object

• Vitalii Zurian: You could also check this answer
• Adib Aroui: But how did you managed to render the template inside a json? Something like json_encode(array('output'=> rendertemplate()))
• Adib Aroui: This maybe will help others to render view as part of a json stackoverflow.com/questions/13257156/…

Answer 1

You can do this:

return $this->getRequest()->isXmlHttpRequest()
 ? $this->render(.... "form.html.twig" ....)
 : $this->render(... full page that will include the form ...) ;

or

if ($this->getRequest()->isXmlHttpRequest()){
 $template = "form.html.twig" ;
 $params = ....
} else {
 $template = "login.html.twig" ;
 $params = ....
}
return $this->render($template, $params) ;

• Adib Aroui: But how to render the template inside a json as OP mentionned?
• Adib Aroui: This maybe will help others to render view as part of a json stackoverflow.com/questions/13257156/…