I have a string with a URL
$string = "http://www.yahoo.com/foo.php?bar=201";
all i want is the query string without everything else.
obviously cant user query_string, help appreciated.
asked Aug 25, 2012 at 6:37
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Your syntax, sense makes none.Norse– Norse2012年08月25日 06:39:47 +00:00Commented Aug 25, 2012 at 6:39
1 Answer 1
$parts = parse_url($string);
echo $parts['query'];
answered Aug 25, 2012 at 6:39
lang-php