0

I'd like to pass arrays through JSON like this:

<?php
for(i=0;i<5;i++) {
 $arrayA[i] = "A" . i;
 $arrayB[i] = "B" . i;
}
echo json_encode($arrayA,$arrayB);
?>

I know it's not possible, but is there other way to pass dynamicly loaded arrays and read them in javascript after that?

asked Jul 19, 2012 at 8:58
2
  • what about this echo json_encode(array($arrayA,$arrayB)); Commented Jul 19, 2012 at 9:01
  • @AdamWaite: That's JavaScript, he's asking for a PHP solution ;-) Commented Jul 19, 2012 at 9:03

4 Answers 4

2

Just put both array in another array.

$returnArr = array($arrayA,$arrayB);
echo json_encode($returnArr);

On JS side just decode with a library of your choice and access the returned array like any normal array.

answered Jul 19, 2012 at 9:00

Comments

2
echo json_encode(array('arrayA' => $arrayA, 'arrayB' => $arrayA));
answered Jul 19, 2012 at 9:01

Comments

1

Just create wrapper for your arrays:

for(i=0;i<5;i++) {
 $arrayA[i] = "A" . i;
 $arrayB[i] = "B" . i;
}
$arrayC = array($arrayA,$arrayB);
echo json_encode($arrayC);

On jQuery side:

$.getJSON('ajax/yourPhpFile.php', function(data) {
 $.each(data, function(key, val) {
 // each `val` is one of the arrays you passed from php
 });
});
answered Jul 19, 2012 at 9:02

Comments

0

You can use AJAX to load up a script that will return a PHP generated array. If you're using jQuery, you call it using either $.get() or $.getJSON(). You can read up on PHP JSON manual here http://php.net/manual/en/book.json.php and on jQuery .getJson() function here http://api.jquery.com/jQuery.getJSON/

answered Jul 19, 2012 at 9:01

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