Calling elements of php array into jquery

Question

I am going to call the elements of the following array into jquery.

$options[] = array( 'title' => 'Upload Favicon',
 'id' => 'favicon',
 'type' => 'upload' );

I have tried the following, but it does not work..

jquery("'.$option['id'].'").hide();

May be I am wrong, but I myself guess that it is because in the jquery code there is no # for id calling, but I do not know how to add #.

Please help..

• Esailija: jQuery("#'.$option['id'].'").hide(); I guess?

Answer 1

The obvious problem is here:

$options[] = array( 'title' => 'Upload Favicon', 
 ^^

This says "add an element to the array $options, and set that element's value to the array 'title' => 'Upload Favicon'.... If $option is not yet set, it will be created as an array. So it will effectively be like this:

$options = array (
 array ('title' => 'Upload Favicon',
 'id' => 'favicon',
 'type' => 'upload'
 );
);

This probably isn't what you mean, simnce you'll need to access it like this:

$options[0]['id']

To fix it, remove the []:

$options = array( 'title' => 'Upload Favicon',
 'id' => 'favicon',
 'type' => 'upload' 
 );

• Esailija: What about the extremely vague jquery("'.$option['id'].'").hide(); it has 2 errors on jQuery alone.
• lonesomeday: @Esailija That could easily be an extract of a coherent PHP statement, if you assume single quotes before and after the jQuery statement. I was presuming this is an extract of a longer statement.