split function in javascript

Question

i have an array which contains different values, i want split them off and print in browser. but i want alert it first value. i have made a function but it is not wokring

<script type="text/javascript">
$(function(){
 var jam= new Array("first","second","third","fourth");
 var Klnew= jam.split(",");
 //for(i=0;i<Klnew.length;i++) {}
 alert(Klnew[0]) 
}); 
</script>

• Engineer: split is the function of String,not of Array.
• sdepold: i'm also wondering what should happen if you call split on an array :D
• gdoron: @sdepold. ohhh, please don't, the world will come to it's end!
• sdepold: @gdoron :D it could probably return an array of arrays. so every string inside the array gets split :D

Answer 1

You can't split an array. It is already split.

You might be looking for something like this:

var foo = ['a', 'b', 'c']; 
console.log(foo.shift()); // Outputs "a"
console.log(foo.join(',')); // Outputs "b,c"

... but it hard to tell what your goals are from your question.

Answer 2

 $(function(){
 var jam= new Array("first","second","third","fourth");
 var Klnew= jam.slice();
 // for(i=0;i<Klnew.length;i++) {}
 alert(Klnew[0])
 })

Answer 3

var jam= new Array("first","second","third","fourth");
alert(jam[0]); // alert before the join.
var Klnew= jam.join(","); // join, not split the array...

Output:

"first,second,third,fourth"

• Jitender: ok thanks but now i want split them and print using document.write
• gdoron: @Quentin. I meant join, sorry.

Answer 4

You would use split for getting an array out of a string:

"first,second,third,fourth".split(',') ==> ['first', 'second', 'third', 'fourth']

Answer 5

split (of string) method splits string to array.

join (of array) method joins array elements into string. So:

arr = Array("first","second","third","fourth");
str = arr.join(",")
alert(str) // will alert "first,second,third,fourth"
alert(arr == str.split(","))// will alert true

• RobG: The second alert is false because both sides are objects and therefore must return false by definition.

Answer 6

even this is going to work--

var jam = new Array("first", "second", "third", "fourth");
alert(jam[0]);