Error "expecting array" with PHP array_flip() function

Question

I recently updated the server on which I work. I have got an error:

"Warning: array_flip() expects parameter 1 to be array, null given in..."

Does someone know how to fix it?

Here is a part of PHP code:

function redirectWrongDep($url) { 
 $deps = @getDepsByIdUrl($url); 
 $depsFlip = array_flip($deps); 
 if ($_GET['dep'] && !in_array($_GET['dep'], $depsFlip)) { header('Location:'.URL); 
 exit(); 
 } 
} 
function getDepsByIdUrl($url) { 
 $sql = "SELECT ws_flash_departement.nom,ws_flash_departement.id_departement FROM ws_flash_departement WHERE ws_flash_departement.no_resultats != 0 AND ws_flash_departement.id_departement IN (SELECT url_departement.id_departement FROM url_departement WHERE url_departement.id_url=" . $url . ") ORDER BY nom ASC"; 
 $result = mysql_query($sql); 
 while ($row = mysql_fetch_assoc($result)) { 
 $deps[$row["id_departement"]]=utf8_encode($row["nom"]); 
 } 
 mysql_free_result($result); 
 return $deps; 
 } 

• The Disintegrator: You are trying to flip a NULL

Answer 1

most likely you updated to an server where magic quotes is set on off

This id because something is returning the value false or not returning true or 1 so debug the code .you are not suplling anything too the array_flip() you have to supply array

example:

$arr = array("a" => 3, "b" => 1, "c" => 2);
$arr = array_flip($arr);
print_r($arr);

Answer 2

array_flip takes an array as first parameter and you give nothing...

PS: Maybe with some lines of code, I could give you a more precise answer

• Pureandfast: Here is a part of PHP code : function redirectWrongDep($url) { $deps = @getDepsByIdUrl($url); $depsFlip = array_flip($deps); if ($_GET['dep'] && !in_array($_GET['dep'], $depsFlip)) { header('Location:'.URL); exit(); } }
• Pureandfast: A second part : function getDepsByIdUrl($url) { $sql = "SELECT ws_flash_departement.nom,ws_flash_departement.id_departement FROM ws_flash_departement WHERE ws_flash_departement.no_resultats != 0 AND ws_flash_departement.id_departement IN (SELECT url_departement.id_departement FROM url_departement WHERE url_departement.id_url=" . $url . ") ORDER BY nom ASC"; $result = mysql_query($sql); while ($row = mysql_fetch_assoc($result)) { $deps[$row["id_departement"]]=utf8_encode($row["nom"]); } mysql_free_result($result); return $deps; }
• Antoine: What's the value returned by getDepsByIdUrl ?
• Pureandfast: This function returns an array of departments (it is a french project). The french Departments are from 1 to 95.
• Antoine: I mean does it return what you are expecting ? Did you print_r this array ?

Answer 3

Check this manual:

http://php.net/manual/en/function.array-flip.php

Eg.

$trans = array("a" => 1, "b" => 1, "c" => 2);
$trans = array_flip($trans);
print_r($trans);