Python calling an executable program

Question

I need to call an executable program with Python, let's say:

C:\Program Files\ANSYS Inc\v140\ansys\bin\winx64\ANSYS140.exe

I would need to have a txt file (afshin.txt) run with this executable application and then get the output file which is a txt file as well. In MATLAB for example it would be:

dos '"C:\Program Files\Ansys Inc\v121\ANSYS\bin\intel\ansys121.exe" -p AA_T_A -b -i afshin.txt -o file01.out' 
mod_1 = load('output_res.txt');

Would you help me to do it in Python?

• Seki: in your example is file01.out same than output_res.txt ?
• Ferdinand Beyer: There are plenty of good examples in the documentation of the subprocess module.
• Seki: yes, and a quick search gives a solution for the first part ; stackoverflow.com/questions/89228/…

Answer 1

Have a look at envoy, a sane wrapper around subprocess:

import envoy
r = envoy.run("C:\Program Files\Ansys Inc\v121\ANSYS\bin\intel\ansys121.exe -p AA_T_A -b -i afshin.txt -o file01.out")
mod_1 = open("output_res.txt").read()
print mod_1

• Colonel Panic: Yes use a high level library not the low level library

Answer 2

I have been use the following lines.

import os;
os.system("\"C:\\Apl\\ANSYS Inc\\v130\\ansys\\bin\\winx64\\ansys130.exe\" -b -j jobname -i InputFile.inp -o jobname.out");