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I'm writing a PHP script to work with some JSON data. Below is an (abridged) var_dump($data). I want to return the value associated with ["[question(13), option(0)]"] which is 20. I can't figure out how to do it. I've tried $data->[question(13), option(0)] and $data->question(13). (I tried to look this up but I'm not sure what the notation means, so I'm not sure what I'm looking for)

object(stdClass)#133 (36) {
 ["id"]=>
 string(1) "1"
 ["contact_id"]=>
 string(0) ""
 ["status"]=>
 string(8) "Complete"
 ["is_test_data"]=>
 string(1) "0"
 ["datesubmitted"]=>
 string(19) "2012-04-19 17:11:00"
 ["[question(5)]"]=>
 string(11) "C. 40%, 40%"
 ["[question(9)]"]=>
 string(47) "D. EBITDA and Free cash flow are the same thing"
 ["[question(10)]"]=>
 string(48) "A. Accounts Payable as % of sales would increase"
 ["[question(11)]"]=>
 string(20) "E. None of the above"
 ["[question(12)]"]=>
 string(97) "A. A larger portion of initial investment is equity which can increase exit return potential."
 ["[question(13), option(0)]"]=>
 string(2) "20"
 ["[url("embed")]"]=>
 string(0) ""
 ["[variable("STANDARD_IP")]"]=>
 string(13) "38.107.74.230"
 ["[variable("STANDARD_LONG")]"]=>
 string(10) "-73.976303"
 ["[variable("STANDARD_LAT")]"]=>
 string(9) "40.761902"
}
asked Apr 25, 2012 at 17:28
1
  • You should really have your properties follow common variable name conventions. Commented Apr 25, 2012 at 17:32

2 Answers 2

3

Either use extended object access notation:

$data->{'[question(13), option(0)]'}

Or just ask for normal array and use it as normal array.

json_decode($json, true);
answered Apr 25, 2012 at 17:30
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2 Comments

Ahhh... the infamous curly brackets. Thanks! Out of curiosity, what does that notation mean? Are those instance variables of an object?
@Emerson: Yes, they are. Check the stackoverflow.com/questions/3737139/… for more information.
1

try this

echo $data->{'[question(13), option(0)]'};
answered Apr 25, 2012 at 17:32

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