Python function accepting an object as a parameter?

Question

So I have the following:

class Tree(object):
 def__init__(self):
 self.right = None
 self.left = None
 self.val = None

I populate the tree with stuff in my code.

I'd like to write a function of the form

def mult(newVal, node)
 newVal = diff(node.left, newVal, var)
 newVal.append('*')
 newval.append(next(node.right))
 newVal.append('+')
 newVal = diff(node.left, newVal, var)
 newVal.append('*')
 newVal.append(next(node.left))

Where next is simply a function that traverses to the next node in the tree, and diff is a recursive function of the following form:

def diff(node, newVal, var):
...
...
 elif(node.val == '*'):
 newVal = diff(node.left, newVal, var)
 newVal.append('*')
 newval.append(next(node.right))
 newVal.append('+')
 newVal = diff(node.left, newVal, var)
 newVal.append('*')
 newVal.append(next(node.left))
...
...

and my "main" is

 node = Tree()
 newEquation = []
 pos = 0
 pos, newTree = buildTree(node, equation, pos)
 newEquation = diff(newTree, newEquation, variable)
 newEquation = ''.join(newEquation)
 print newEquation

How would I write the def mult() function to accept a tree node as a parameter, and then call the diff() function again?

• Ignacio Vazquez-Abrams: What's wrong with how you've written it?
• gfppaste: it's fixed, a syntax error was throwing a strange error message. Thanks!

Answer 1

Python is not typed, so if you call mult with:

mult(newEquation, node)

That should work just fine.