passing function as parameter

Question

I got two functions, passing one of then as parameter, like:

var a = function(f)
{
 // some code
 f();
};
var b = function()
{
};
a(b); // works great, the function a is executed, then the function b is executed

Now I need to extend it to tree functions, like:

var a = function(f)
{
 // some code
 f();
};
var b = function(f)
{
 // some code
 f();
};
var c = function()
{
};
a(b(c)); // but it does not work. b(c) words like a method and get executed right on the instruction.

How can i do that?

Answer 1

Pass a wrapper function that executes b(c):

a(function() {
 b(c);
});

Answer 2

It sounds like you want to use a callback kind of pattern. Instead of simply passing along the results of the functions, you would do something like so:

var a = function(callback)
{
 // Do Stuff
 callback();
}
var b = function(callback)
{
 // Do Stuff
 callback();
}
var c = function() { }

Your code would end up looking like so:

a(function()
{
 b(function()
 {
 c();
 });
});

Effectively, you pass along another function to execute after the method finished. In the above scenario, I simply supply two anonymous functions as the callback arguments.

Answer 3

function a(f){
 // code
 f()
}
function b(f){
 // code
 a(f())
}
function c(){
 //code
}
b(c);

Answer 4

One way would be to use an anonymous function:

a(function() { b(c); });