Taking multiple inputs in python

Question

I am writing a python program which no. of string user wants to enter as integer and then takes N number of strings from user and then separates strings based on their index and print even strings and odd string separated by space.

For Example: Inputs from user: 1

and output: 2

and had written this code in pycharm IDE:

 tc=input("Enter the no. of test cases you want: ")
 
 
 for j in range((int(tc))):
 n=list(map(int,input("Enter a string: ").split()))
 continue
 print(1)
 
 for i in range(len(n)):
 if i%2==0:
 print(n[i],end="")
 print(end=" ")
 for i in range(len(n)):
 if i%2!=0:
 print(n[i],end="")

but the problem I am facing is that when I input first string(hacker) and then it will ask for second input and when I input second string(sand) and press enter then it gives output of second string only(sn ad), however I want output as shown in the image above.

• quamrana: Please update your question with the text of the sample input and required output.

Answer 1

You need to collect the inputs and then apply the same transformation to each one:

tc = input("Enter the no. of test cases you want: ")
s = []
for j in range((int(tc))):
 s.append(input("Enter a string: "))
for n in s:
 for i in range(len(n)):
 if i % 2 == 0:
 print(n[i], end="")
 print(end=" ")
 for i in range(len(n)):
 if i % 2 != 0:
 print(n[i], end="")
 print()

Output:

hce akr
sn ad

Not quite as you specify.

Answer 2

A simple answer for your question

n = int(input())
strings = [input() for _ in range(n)]
result = []
for string in strings:
 string_odd = string[::2]
 string_even = string[1::2]
 string = string_odd+' '+string_even
 result.append(string)
for res in result:
 print(res)

Output

hce akr
sn ad