String to array of integer

Question

I have a string '[1. 2. 3. 4. 5.]' and I would like to convert to get only the int such that i obtain an array of integer of [1, 2, 3, 4, 5]

How do I do that? I tried using map but unsuccessful.

Answer 1

Use strip for remove [], split for convert to list of values which are converted to int in list comprehension:

s = '[1. 2. 3. 4. 5.]'
print ([int(x.strip('.')) for x in s.strip('[]').split()])
[1, 2, 3, 4, 5]

Similar solution with replace for remove .:

s = '[1. 2. 3. 4. 5.]'
print ([int(x) for x in s.strip('[]').replace('.','').split()])
[1, 2, 3, 4, 5]

Or with convert to float first and then to int:

s = '[1. 2. 3. 4. 5.]'
print ([int(float(x)) for x in s.strip('[]').split()])
[1, 2, 3, 4, 5]

Solution with map:

s = '[1. 2. 3. 4. 5.]'
#add list for python 3
print (list(map(int, s.strip('[]').replace('.','').split())))
[1, 2, 3, 4, 5]