Parsing function arguments based on pattern

Question

I'm completely stumped as to how to do this. I've been trying for a while, but can't find a suitable way.

So, let's say that I have a pattern representing a function with two arguments: function_name(arg0, arg1).

How can I get the values of arg0 and arg1?

Sample input would look like function_name(10, 20), function_name(function_name(15 + 2, 16), 6) and such.

Another pattern would be function_2[arg0](arg1).

So basically, how can I find strings that match this sort of pattern and extract the values of the arguments?

Answer 1

you can use module re for regex pattern matching:

In [27]: import re
 ...: s='function_name(10, 20)'
 ...: m=re.search(r'\((.*),(.*)\)', s)
 ...: m.groups()
Out[27]: ('10', ' 20')
In [28]: arg1, arg2 = m.groups()
 ...: print arg1, arg2
 ...: 
10 20