I need to specify the string find in Regex format, in order that head tag can be found whatever its format is like <html > or <html> or < html>. How to specify the find string in Regex format?
String source = "<html >The quick brown fox jumps over the brown lazy dog.</html >";
String find = "<html>";
String replace = "";
Pattern pattern = Pattern.compile(find);
Matcher matcher = pattern.matcher(source);
String output = matcher.replaceAll(replace);
System.out.println("Source = " + source);
System.out.println("Output = " + output);
kiritsuku
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asked Sep 7, 2012 at 12:03
user1321824
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4 Answers 4
Although you could go round your problem by doing <\\s*html\\s*>, you should not process HTML with regex. Obligatory link.
The \\s* denotes 0 or more white spaces.
answered Sep 7, 2012 at 12:08
npinti
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Do not attempt to parse HTML using regex! Try reading about XPath. Very helpful.
Although XPath will try by default to validate your document, but you can try HtmlCleaner to make it valid.
answered Sep 7, 2012 at 12:11
Andrei Sfat
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To extract text inside your tags use something like
String source = "<html >The quick brown fox jumps over the brown lazy dog.</html >";
System.out.println( source.replaceAll( "^<\\s*html\\s*>(.*)<\\s*\\/html\\s*>$", "1ドル" ) );
// output is:
// The quick brown fox jumps over the brown lazy dog.
But try to avoid parsing of html by regexps. Read this topic.
answered Sep 7, 2012 at 12:09
stemm
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This example may be helpful to you.
String source = "<html >The quick brown fox jumps over the brown lazy dog.</html >";
String find = "\\<.*?>";
String replace = "";
Pattern pattern = Pattern.compile(find);
Matcher matcher = pattern.matcher(source);
String output = matcher.replaceAll(replace);
System.out.println("Source = " + source);
System.out.println("Output = " + output);
answered Sep 7, 2012 at 12:14
Biswajit
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lang-java
<html <!-- <html> --> >valid html?