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I'm using MultipartPostHandler in file sending. My code is following:

params = {'file':open(file_name, 'rb')} 
headers = {'cookie':session_id}
urllib2.install_opener(urllib2.build_opener(MultipartPostHandler.MultipartPostHandler))
response = urllib2.urlopen(urllib2.Request("www.example.com/upload", params, headers))

How could I do the same (send file to the server) without using MultipartPostHandler? It would be good to use only buid-in python modules and urllib2. Is it possible.

asked Apr 2, 2012 at 8:22
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  • What is the problem with MultipartPostHandler? It only uses built-ins, is freely licensed and the source code is available online. Commented Apr 2, 2012 at 8:31
  • MultipartPostHandler needs to install it using easy_install, pip or from source. I want like to write the python script that would not require new instalations. Commented Apr 2, 2012 at 9:20

2 Answers 2

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MultipartPostHandler needs to install it using easy_install, pip or from source. I want like to write the python script that would not require new instalations.

Just add it to your original script - it is just one file. Copy paste the code for the module.

answered Apr 2, 2012 at 10:24
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Unfortunately, there is no direct method available to post a multiple part file using urllib2. But there are ways to accomplish that by writing a custom form object using mimetype and mimetools module. You could follow this recipe and adopt your form to do a mutipart upload using urllib2.

(In Python3, urllib.request data can take a pointer to file object and that does read the whole file into memory)

answered Apr 2, 2012 at 8:38

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