Remove values from subarrays javascript

Since you have nested arrays you will have to combine map and filter. Map to iterate the top level and filter or splice (depending on your logic) - on the sub to remove or filter out items.

topArray.map(subArray => subArray.filter(item => ...))

or

topArray.map(subArray => subArray.splice(start, deleteCount)

If you then want to "flatten" the results you can add .flat() or .flatMap() to the end (depending on your logic)

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array

If you know that you just want to grab the first item on each sub-array, you can:

topArray.map(subArray => subArray[0])

I would personnaly recommand using map which here takes for each element in your array, the second element (which is your object)

const arr = [
 ["2021-07-06T00:00:00Z", {type:"meeting",id:"123"}],
 ["2021-08-06T00:00:00Z", {type: "call", id: "456"}],
 ["2021-09-06T00:00:00Z", {type: "zoom", id: "789"}]
];
console.log(arr.map(item => item[1]))

Here's how you can do it:

let result = [];
let arr = [
 ["2021年07月06日T00:00:00Z", {type:"meeting",id:"123"}],
 ["2021年07月06日T00:00:00Z", {type: "call", id: "456"}]
];
result = arr.map((item)=>{
 return item[1];
})
console.log(result);

You can use a slice to remove the first element of each subarray. And a flatMap to join all the filtered subarrays into one single array.

Here's how I would do it:

const filteredArray = array.flatMap((subarray) => subarray.slice(1));

use Map with filter

var a = [[1,2], [3,4]]
console.log(a.map((b) => b.filter((c, i) => i != 0)))

Result

[[2], [4]]

• javascript