1 
let arr1 = [['item 1', 'item 2'],['item 3', 'item 4']]
let arr2 = ['item 1', 'item 2']

I need to check whether arr2 exist in arr1

asked May 24, 2021 at 17:07
2
  • You will have to use some and every. Does the order matter? Commented May 24, 2021 at 17:11
  • This is a very popular gist that tackle this: jsfiddle.net/SamyBencherif/8352y6yw Commented May 24, 2021 at 17:26

3 Answers 3

3

You can use Array#some along with Array#every.

let arr1 = [
 ['item 1', 'item 2'],
 ['item 3', 'item 4']
]
let arr2 = ['item 1', 'item 2']
let res = arr1.some(x => x.length === arr2.length && x.every((e, i) => e === arr2[i]));
console.log(res);

answered May 24, 2021 at 17:15
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3 Comments

Thanks for the answer, now If I want to delete that item how can I?
You can use arr1.splice(arr1.findIndex(x => x.length === arr2.length && x.every((e, i) => e === arr2[i])), 1)
@geekglance No problem.
1

To keep it simple you can use the combination of every and some as below, it returns true if exists and false if not

arr1.some(i => i.length === arr2.length && i.every(it => arr2.includes(it)))
answered May 24, 2021 at 17:12

2 Comments

If I want to delete that item how can i?
1 . You can use findIndex and splice let res = arr1.findIndex(x => x.length === arr2.length && x.every((e, i) => e === arr2[i])); arr1.splice(0,1); 2. you can directly use filter arr1 = arr1.filter(x => x.length !== arr2.length || x.some((e, i) => e !== arr2[i]));
0

If you want a very quick and easy way to check, you could do:

arr1.findIndex(arr => { return JSON.stringify(arr) === JSON.stringify(arr2) })

Which will return the position of arr2 within arr1, or '-1' if it does not exist in arr1

answered May 24, 2021 at 17:12

1 Comment

Quick note: This will only work if you are trying to match the order (which you might be seeing as in JS arrays are ordered)

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