2D Array to 3D Array Javascript (Google Script)

Question 1

If I have an array:

var arr = [ 
 [1,2,3,4,5,6,7,8,9] , 
 [11,12,13,14,15,16,17,18,19] 
 ];

How could I convert to

var newArr = [ 
 [ [1],[2],[3],[4],[5],[6],[7],[8],[9] ] , 
 [ [11],[12],[13],[14],[15],[16],[17],[18],[19] ] 
 ]

I tried start from something like while(arr.length) newArr.push(arr.splice(0,1)); but I am getting nowhere.

Question 2

I don't know if Google Apps Script has Array#map, but if so, this is the classic use case for it: You want to transform all of the entries in the map into new entries:

var arr = [ 
 [1,2,3,4,5,6,7,8,9] , 
 [11,12,13,14,15,16,17,18,19] 
];
arr = arr.map(function(sub) {
 return sub.map(function(entry) {
 return [entry];
 });
});
console.log(arr);

.as-console-wrapper {
 max-height: 100% !important;
}

If not, or if you don't like all those callbacks, nested for loops would do it:

var arr = [ 
 [1,2,3,4,5,6,7,8,9] , 
 [11,12,13,14,15,16,17,18,19] 
];
for (var i = 0; i < arr.length; ++i) {
 var sub = arr[i];
 for (var j = 0; j < sub.length; ++j) {
 sub[j] = [sub[j]];
 }
}
console.log(arr);

.as-console-wrapper {
 max-height: 100% !important;
}

Question 3

You can simply map old array to the new one.

var newArray = arr.map( second => second.map( third => [ third ] ))

Or more backwards compatible version

var newArray = []
for(var i = array.length - 1; i >= 0; i—-){
 var second = array[i];
 newArray[i] = []
 for(var j = second.length - 1; j >= 0; j—-){
 newArray[i][j] = [ second[j] ]
 }
}

Question 4

Google Apps Script is roughly ES3 compatible (roughly). No chance of arrow functions, I'm not even sure of Array#map.

Question 5

Is this better? (There might be a typo, did it on iPad)

Question 6

A simple solution without ES6 could be:

var arr = [ 
 [1,2,3,4,5,6,7,8,9] , 
 [11,12,13,14,15,16,17,18,19] 
 ];
var newArr = [];
arr.forEach(function(data,index){
 newArr[index] = [];
 data.forEach(function(d){
 var temp = [];
 temp.push(d);
 newArr[index].push(temp);
 });
})
console.log(newArr);

Question 7

Look into Array#map. If you're creating an array, then looping through another and pushing entries in the one you just created, you want map.

Question 8

Recursive solution:

var arrayify = function(input) {
 var ret = [];
 if(Array.isArray(input)) {
 input.forEach(function(element) {
 ret.push(arrayify(element));
 });
 } else {
 ret.push(input);
 }
 return ret;
};
var arr = [ 
 [1,2,3,4,5,6,7,8,9], 
 [11,12,13,14,15,16,17,18,19] 
];
var newArray = arrayify(arr);
console.log(newArray);

Question 9

Inefficient alternative for variety:

arr = [ [1,2,3,4,5,6,7,8,9], [11,12,13,14,15,16,17,18,19] ]
newArr = JSON.parse( JSON.stringify(arr).replace(/[^[,\]]+/g, '[$&]') )
console.log( newArr )

T.J. Crowder 1.1m201 gold badges2k silver badges2k bronze badges · Accepted Answer · 2018-01-27 18:20:57Z

I don't know if Google Apps Script has Array#map, but if so, this is the classic use case for it: You want to transform all of the entries in the map into new entries:

var arr = [ 
 [1,2,3,4,5,6,7,8,9] , 
 [11,12,13,14,15,16,17,18,19] 
];
arr = arr.map(function(sub) {
 return sub.map(function(entry) {
 return [entry];
 });
});
console.log(arr);

.as-console-wrapper {
 max-height: 100% !important;
}

If not, or if you don't like all those callbacks, nested for loops would do it:

var arr = [ 
 [1,2,3,4,5,6,7,8,9] , 
 [11,12,13,14,15,16,17,18,19] 
];
for (var i = 0; i < arr.length; ++i) {
 var sub = arr[i];
 for (var j = 0; j < sub.length; ++j) {
 sub[j] = [sub[j]];
 }
}
console.log(arr);

.as-console-wrapper {
 max-height: 100% !important;
}

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