Javascript - add parameters to a function passed as a parameter

You can always use the bind() function to pass some arguments to your function. It'll create a new function with the first argument - arg1 - equal to the value of 3 in this example:

function one(func){
 func(5);
}
function two(arg1, arg2){
 console.log(arg1);
 console.log(arg2);
}
one(two.bind(null, 3))

You can read more about the bind() function here: MDN - Bind

Some workaround is possible

function one() {
 var args = Array.prototype.slice.call(arguments);
 var func = args[0];
 args.splice(0, 1);
 args.push(5);
 func.apply(this, args);
}
function two(arg1, arg2) {
 console.log(arg1);
 console.log(arg2);
}
one(two, 3)

There's a problem with your syntax: function one is expecting its single argument to be a function. Then, below, when you invoke it, you are not passing the function two, but whatever two returns when it's passed a single argument, probably undefined. I don't know what specifically you're trying to accomplish but I'd recommend a little research into closures.

function one(arg){
 two(arg, 5); // func here is two so it requires two params...
}
function two(arg1, arg2){
 console.log(arg1);
 console.log(arg2);
}
one(3)// one expect function so can't execute function here!

as soon as one expects function as argument two(3) should return function.
this condition is required so in order to achieve it your two function should be

function two(arg1){
 console.log(arg1);
 return function(arg2) {
 console.log(arg2);
 };
}

so two(3) function call gets passed as argument to one
so before assigning value to variable engine executes it. And execution of two(3) call logs 3 to console and returns function

 function(arg2) {
 console.log(arg2);
 };

and then engine assigns executed value(returned function) to func variable. so func parameter of one function now looks like

func = function(arg2) {
 console.log(arg2);
 };

one calls func with 5 passed in as argument. so 5 gets logged to console.

Basically you can't specify the parameter in the function or it'll run. You need to specify the function aka one(two), but that obviously wouldn't work.

However if you dynamically create a function you should be able to accomplish the task like so :

function one(func){
 func(5);
}
function two(arg1, arg2){
 console.log(arg1);
 console.log(arg2);
}
one(function(val) { two(3, val) }) //prints 3, 5

well somehow this things work for me

function one(func){
 console.log("one is running");
 func;
}
function two(args1, args2){
 console.log("two is running");
 console.log("args1 -> " + args1);
 console.log("args2 -> " + args2);
}
//to call it
args1 = 6;
args2 = 12
one(two(args1,args2));

• javascript
• function
• parameter-passing