Python during runtime does not consider a number entered as a int or float

Code after print('You cannot enter text, please use numbers') is not required. Due this code, it is stucked in infinite loop once you enter wrong input

Since input is asked in while loop, user input will be asked though the wrong input is given.

Code (Check comments):

while True:
#Get input
userinput= input(" 1 Enter the temperature in celsius: "
 " Enter Quit if you want to close the converter")
#Check user wants to quit
if userinput.lower()=='quit':
 print('Closing the application. Thanks for using the converter')
 break
try:
 #Check type of userinput
 print "Type is =",type(userinput)
 #Check user input is number
 userinput= float(userinput)
 f=userinput*9.0/5+32
 print('Your input was:',userinput,'\n'*2,'The corresponding Fareinheit is',f,'\n'*3, '---'*25)
except ValueError:
 #If user input is not number, then print error message.
 #After this, again user input will be asked due to while loop.
 print('You cannot enter text, please use numbers')

Output:

 C:\Users\dinesh_pundkar\Desktop>python c.py
 1 Enter the temperature in celsius: Enter Quit if you want to close the conve
rter"57"
Type is = <type 'str'>
('Your input was:', 57.0, '\n\n', 'The corresponding Fareinheit is', 134.6, '\n\
n\n', '-------------------------------------------------------------------------
--')
 1 Enter the temperature in celsius: Enter Quit if you want to close the conve
rter"asd"
Type is = <type 'str'>
You cannot enter text, please use numbers
 1 Enter the temperature in celsius: Enter Quit if you want to close the conve
rter"34"
Type is = <type 'str'>
('Your input was:', 34.0, '\n\n', 'The corresponding Fareinheit is', 93.2, '\n\n
\n', '--------------------------------------------------------------------------
-')
 1 Enter the temperature in celsius: Enter Quit if you want to close the conve
rter"quit"
Closing the application. Thanks for using the converter
C:\Users\dinesh_pundkar\Desktop>

Also, if you are using Python 2, then use raw_input instead of input. For Python 3 input works.

Not sure if I understand the problem correctly, but usually it is better to use raw_input instead of input in case like this.

You are using three nested while loops here for no obvious resons. When the user enters a wrong value, he gets transferred to the next while loop which never ends. This is a quick and dirty solution.

# Program to convert Celsius to Fahrenheit
import time
while True:
 userinput= input(" 1 Enter the temperature in celsius: "
 "Enter Quit if you want to close the converter")
 try:
 userinput= float(userinput)
 type(userinput) 
 userinput=float(userinput)
 f=userinput*9.0/5+32
 print('Your input was:',userinput,'\n'*2,'The corresponding Fareinheit is',f,'\n'*3, '---'*25)
 except ValueError:
 print('You cannot enter text, please use numbers') 
 if userinput.lower()=='quit':
 print('Closing the application. Thanks for using the converter')
 break

the problem is here:

if type(userinput)!=str:

since input returns a string, userinput is always a string: Thus, the above snippet is always false. you should try parsing it as a float like in this answer

In the 1 input, you cast it, in the second one, you never cast.

I also noticed, you never actually implemented the "quit" functionality for that loop. This should make your code a bit easier to read.

def checkToClose(value):
 if (value.lower() == 'quit')
 quit()
while True:
 userinput= input(" 1 Enter the temperature in celsius: "
 "Enter Quit if you want to close the converter")
 checkToClose(userinput)
 try:
 userinput= float(userinput)
 catch:
 continue
 f = userinput * 9.0 / 5 + 32
 print('Your input was:',userinput,'\n'*2,'The corresponding Fareinheit is',f,'\n'*3, '---'*25)

• python
• input