5

I have multiple sub-strings that I want to find in a single string and if all three are found then do this, if not, do something else.

I am kind of stuck on how to set it so that if I get three "True", I want to execute something, other I want it to do something else.

Many thanks.

My code is below. 

//Main String
var string0 = ' ": {"MATHEMATICS": {"status": "start", "can_start": false}, "READING": {"status": "start", "can_start": false}, "WRITING": {"status": "start", "can_start": false" ';
//Substrings
var substringArray = ['"MATHEMATICS": {"status": "start"', '"READING": {"status": "start"', '"WRITING": {"status": "start"'];
//Check if Substrings are found in MainString
for (l = 0; l < substringArray.length; l++) {
 if (string0.indexOf(substringArray[l]) > -1) {
 logger.info("True");
 } else {
 logger.info("False");
 }
}
James Vu
2,4833 gold badges16 silver badges33 bronze badges
asked Jun 9, 2016 at 0:35

4 Answers 4

4

You can try use Array.every method to check for all the substrings.

An example of code:

var isContainsAllTheParts = substringArray.every(function(substring){
 return string0.indexOf(substring) >= 0;
});
answered Jun 9, 2016 at 0:56
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Comments

2

Simply use a variable to count the number of "true"

 //Main String
 var string0 = ' ": {"MATHEMATICS": {"status": "start", "can_start": false}, "READING": {"status": "start", "can_start": false}, "WRITING": {"status": "start", "can_start": false" ';
 //Substrings
 var substringArray = ['"MATHEMATICS": {"status": "start"', '"READING": {"status": "start"', '"WRITING": {"status": "start"'];
 var matchCount = 0;
 //Check if Substrings are found in MainString
 for (l = 0; l < substringArray.length; l++) {
 if (string0.indexOf(substringArray[l]) > -1) {
 logger.info("True");
 matchCount++;
 } else {
 logger.info("False");
 }
 }
 if(matchCount == 3){
 //do something
 logger.info('I did');
 } else {
 // do some other thing
 logger.info('I did not');
 }

answered Jun 9, 2016 at 0:51

2 Comments

Thanks, we posted at the same time! I have marked yours as the answer. Thank you :)
use substringArray.length instead of hard coded 3, then it will work for any number of elements in substringArray
1

Not sure why Telman Ahababov's answer wasn't accepted. I'll explain it in case it wasn't clear enough. I'm also shortening it up a bit more and using the simpler includes() method:

let str = "Here is the string in which we want to find multiple substrings."
let subStrArr = ["Here is", "which we", "multiple"]
let containsAllSubStrs = subStrArr.every(subStr => {
 return str.includes(subStr);
 });
if (containsAllSubStrs) {
 //containsAllSubStrs equals 'true', meaning all substrings were found.
} else {
 //containsAllSubStrs equals 'false', meaning NOT all substrings were found.
 }
answered Nov 12, 2020 at 20:17

Comments

0

I figured out a way to do it.

var magicNumber = 0;
//Check if Substrings are found in string0
for (l = 0; l < substringArray.length; l++) {
 //logger.info(substringArray[l]);
 if (string0.indexOf(substringArray[l]) > -1) {
 logger.info("True");
 magicNumber++;
 } else {
 logger.info("False");
 }
}
while (magicNumber < 3) {
 //execute this
}

answered Jun 9, 2016 at 0:51

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