I see many topics on this site, but every one deal with single Array.
My need is to convert every object with number as key to array.
For exemple, I have an object like :
{
"parent":{
"0":{
"child":false
},
"1":{
"child":false
},
"4": {
"child":false
}
}
}
And i would like
{
"parent": [
{
"child":false
},
{
"child":false
},
null,
null,
{
"child":false
}
]
}
This is an exemple, my object can be really deep and content many object like this, so i need a generic function.
UPDATE
My try sor far using code of @Nenad Vracar :
function recursiveIteration(object) {
var newob = {};
for (var property in object) {
if (object.hasOwnProperty(property)) {
if (typeof object[property] == "object"){
var result = {};
var keys = Object.keys(object[property]);
if ($.isNumeric(keys[0])) {
console.log("======> "+property+" is table");
for (var i = 0; i <= keys[keys.length - 1]; i++) {
if (keys.indexOf(i.toString()) != -1) {
result[property] = (result[property] || []).concat(object[property][i]);
} else {
result[property] = (result[property] || []).concat(null);
}
}
newob[property] = result;
recursiveIteration(object[property]);
}
newob[property] = object[property];
recursiveIteration(object[property]);
}else{
newob[property] = object[property];
}
}
}
return newob;
}
And the JSFiddle for live try
Thanks you guys !
asked Jun 2, 2016 at 7:33
Jax Teller
1,4772 gold badges15 silver badges25 bronze badges
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And what have you tried to achieve it ?Rayon– Rayon2016年06月02日 07:35:44 +00:00Commented Jun 2, 2016 at 7:35
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what is null, null?Rahul Arora– Rahul Arora2016年06月02日 07:38:53 +00:00Commented Jun 2, 2016 at 7:38
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What do you mean by deep?Is there any nesting to nth level?RIYAJ KHAN– RIYAJ KHAN2016年06月02日 07:39:09 +00:00Commented Jun 2, 2016 at 7:39
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@Rahul Arora null, null, is index 2 and 3.Jax Teller– Jax Teller2016年06月02日 07:40:03 +00:00Commented Jun 2, 2016 at 7:40
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@RIYAJ KHAN I mean i can have object, in object in object, etc...Jax Teller– Jax Teller2016年06月02日 07:41:15 +00:00Commented Jun 2, 2016 at 7:41
3 Answers 3
I think this is what you want:
var data = {
"parent": {
"0": {
"child": false
},
"1": {
"child": false
},
"4": {
"child": false
}
}
};
var convert = function(data) {
// not an object, return value
if (data === null || typeof data !== 'object')
return data;
var indices = Object.keys(data);
// convert children
for (var i = 0; i < indices.length; i++)
data[indices[i]] = convert(data[indices[i]]);
// check if all indices are integers
var isArray = true;
for (var i = 0; i < indices.length; i++) {
if (Math.floor(indices[i]) != indices[i] || !$.isNumeric(indices[i])) {
isArray = false;
break;
}
}
// all are not integers
if (!isArray) {
return data;
}
// all are integers, convert to array
else {
var arr = [];
for (var i = 0, n = Math.max.apply(null, indices); i <= n; i++) {
if (indices.indexOf(i.toString()) === -1)
arr.push(null);
else
arr.push(data[i]);
}
return arr;
}
};
console.log( convert(data) );
Here is a working jsfiddle with the data you provided in the update.
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1 Comment
Jax Teller
Hey man, that's perfect, thanks you so much, and thanks to everyone try to help me !
You can do this with Object.keys() and one for loop
var data = {"parent":{"0":{"child":false},"1":{"child":false},"4":{"child":false}}}, result = {}
var keys = Object.keys(data.parent);
for (var i = 0; i <= keys[keys.length - 1]; i++) {
if (keys.indexOf(i.toString()) != -1) {
result.parent = (result.parent || []).concat(data.parent[i]);
} else {
result.parent = (result.parent || []).concat(null);
}
}
console.log(result)
answered Jun 2, 2016 at 7:53
Nenad Vracar
122k16 gold badges160 silver badges184 bronze badges
1 Comment
Jax Teller
Thats the idea ! But as i said i need a generic function for doing it, key are never the same, etc...But thanks, i'll try to do it based on your code.
You might achieve this job with a very simple recursive Object method as follows. Any valid nested object (including arrays) within an object structure will be converted into an array, in which the properties are replaced with indices and values are replaced by items.
Object.prototype.valueToItem = function(){
return Object.keys(this).map(e => typeof this[e] === "object" &&
this[e] !== null &&
!Array.isArray(this[e]) ? this[e].valueToItem()
: this[e]);
};
var o = { name: "terrible",
lastname: "godenhorn",
cars: ["red barchetta", "blue stingray"],
age: 52,
child: { name: "horrible",
lastname: "godenhorn",
cars: ["fiat 124", "tata"],
age: 24,
child:{ name: "badluck",
lastname: "godenhorn",
cars: ["lamborghini countach"],
age: 2,
child: null}}},
a = o.valueToItem();
console.log(a);Ok modified to the OP's conditions but still generic as much as it can be.
Object.prototype.valueToItem = function(){
var keys = Object.keys(this);
return keys.reduce((p,c) => typeof this[c] === "object" &&
this[c] !== null &&
!Array.isArray(this[c]) ? keys.every(k => Number.isInteger(k*1)) ? (p[c] = this[c].valueToItem(),p)
: this[c].valueToItem()
: this
,new Array(~~Math.max(...keys)).fill(null));
};
var o = {
parent: {
0: {
child : false
},
1: {
child : false
},
4: {
child : {
0: {
child : false
},
3: {
child : false
},
5: {
child : false
}
}
}
}
};
a = o.valueToItem();
console.log(JSON.stringify(a,null,4));
answered Jun 2, 2016 at 10:36
Redu
26.3k6 gold badges61 silver badges84 bronze badges
5 Comments
pishpish
This will convert every object to an array, effectively losing all property names.
Redu
@janje Exactly... this is what it does. That's why it's called
valueToItem()pishpish
That is not what the OP wants to do. Check my answer for the correct behaviour.
Jax Teller
Yeah, this is not exactly what i want, but your code is interesting. If i had a better knowledge on javascript i could edit it for my need, but i'm not good enought for it :/
Redu
@A. Rossi OK have corrected the above code according to what i think you want :)
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