if statement not reading characters in string

By the way, the error in your method is in the third condition -

and plate[3] >= "0" and plate[1] <= "9" <-------- Notice that you are using `plate[1]` instead of [3]

Change it to -

and plate[3] >= "0" and plate[3] <= "9"

A simple regex will do this job.

re.match(r'[A-Z]{3}[0-9]{3}$', s)

Since re.match tries to match from the begining of the string, you don't need to use start of the line anchor ^.

Example:

>>> import re
>>> def check(s):
 if re.match(r'[A-Z]{3}[0-9]{3}$', s):
 print('works')
 else:
 print('Not work')
>>> check(input('Enter the lisence plate number: '))
Enter the lisence plate number: ABC123
works
>>> check(input('Enter the lisence plate number: '))
Enter the lisence plate number: ABCDEF
Not work
>>> 

on line :

and plate[3] >= "0" and plate[1] <= "9"\

change '1' to '3' like this:

and plate[3] >= "0" and plate[3] <= "9"\

Your bug is a typo.

 and plate[3] >= "0" and plate[1] <= "9"\

versus

 and plate[3] >= "0" and plate[3] <= "9"\

Also, the indentation of print(verd) is off; it's in the else block, so it would only print anything if the license wasn't valid.

Here's your code with minimal changes to get it working:

#Get data from user
plate = input('Enter the lisence plate number: ')
#Determine if style is old or new
if len(plate) == 6 and plate[0] >= "A" and plate[0] <= "Z"\
 and plate[1] >= "A" and plate[1] <= "Z"\
 and plate[2] >= "A" and plate[2] <= "Z"\
 and plate[3] >= "0" and plate[3] <= "9"\ # Fixed bug here
 and plate[4] >= "0" and plate[4] <= "9"\
 and plate[5] >= "0" and plate[5] <= "9":
 verd = 'works'
else:
 verd = 'Not work'
#print results
print(verd) # Fixed bug here

However, your code has a few other issues, so here's an improved version:

# Get data from user
plate = input('Enter the license plate number: ')
# Determine if style is old or new
if (len(plate) == 6 and
 'A' <= plate[0] <= 'Z' and
 'A' <= plate[1] <= 'Z' and
 'A' <= plate[2] <= 'Z' and
 '0' <= plate[3] <= '9' and
 '0' <= plate[4] <= '9' and
 '0' <= plate[5] <= '9'):
 verd = 'Valid'
else:
 verd = 'Invalid'
print(verd)

You could also do this:

# Get data from user
plate = input('Enter the license plate number: ')
# Determine if style is old or new
if (len(plate) == 6 and
 plate[:3].isupper() and plate[:3].isalpha() and
 plate[3:].isdigit():
 verd = 'Valid'
else:
 verd = 'Invalid'
print(verd)

But generally, I would say the best/cleanest way is the regular expression method:

import re
plate = input('Enter the license plate number: ')
if re.match(r'^[A-Z]{3}[0-9]{3}$', plate):
 print('Valid')
else:
 print('Invalid')

• python