I have the code to print out time in the following format: 00 01 02 03 04 05 06 07 08 09 10 11... only that the first number (0) needs to be above the second number (0).. Below is what I have
#include <iostream>
using namespace std;
void printArray (int arg[], int length) {
for (int n=0; n<length; ++n)
cout << arg[n] << ' ';
cout << '\n';
}
int main()
{
int ftime[99] = {0,0,0,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,2};
int ttime[99] = {0,1,2,3,4,5,6,7,8,9,0,1,2,3,4,5,6,7,8,9,0};
cout << "Time: ";printArray(ftime,21);
cout << " ";printArray(ttime, 21);
return 0;
}
Now the following prints out:
Time: 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 2
0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0
Which is exactly what I want, but I need to do this all the way to 99 and was wondering if there is an easier way to initialize both the ftime and ttime arrays other than the way I did it. Any input would be greatly appreciated!
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"if there is an easier way to initialize both" Depends on the number schemes you need to store in the arrays.πάντα ῥεῖ– πάντα ῥεῖ2014年10月30日 18:47:58 +00:00Commented Oct 30, 2014 at 18:47
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you may use loops to feed in the dataDr. Debasish Jana– Dr. Debasish Jana2014年10月30日 18:48:05 +00:00Commented Oct 30, 2014 at 18:48
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Can't you just loop to create the arrays? We are actually not sure why you created a restriction for yourself by trying to initialize the array during declarationTitus– Titus2014年10月30日 18:50:10 +00:00Commented Oct 30, 2014 at 18:50
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You don't even need arrays, really.Greg Hewgill– Greg Hewgill2014年10月30日 18:51:04 +00:00Commented Oct 30, 2014 at 18:51
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2You have a really wide monitor.Barry– Barry2014年10月30日 18:51:42 +00:00Commented Oct 30, 2014 at 18:51
7 Answers 7
Just feed it with a loop.
#include <iostream>
using namespace std;
void printArray (int arg[], int length) {
for (int n=0; n<length; ++n) {
cout << arg[n] << ' ';
}
cout << '\n';
}
int main()
{
int ftime[100];
int ttime[100];
for (int i = 0; i < 100; i++) {
ftime[i] = i / 10;
ttime[i] = i % 10;
}
cout << "Time: ";
printArray(ftime,100);
cout << " ";
printArray(ttime,100);
return 0;
}
answered Oct 30, 2014 at 18:52
merlin2011
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1 Comment
Freddy Rivas
The initial ftime for this one is a 9 instead of a 0.. so it starts as 09 01 02 03...
Simple loop would do it.
int j = -1;
for(unsigned int i = 0; i < 99; ++i) {
ttime[i] = i % 10;
if(i % 10 == 0) {
++j;
}
ftime[i] = j;
}
Comments
something like this?
int ftime[99];
int i;
for (i=0; i < 99; i++) {
if (i/2 == 1)
ftime[i] = 1;
else if (i==20)
ftime[i] = 2;
else
ftime[i] = 0;
}
for (i=0; i < 99; i++) {
if (i/2 < 2)
ttime[i] = i % 10;
else
ttime[i] = 0;
}
answered Oct 30, 2014 at 18:51
Dr. Debasish Jana
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Comments
You could do a dual-layered for-statment example:
int k = 0;
for(int i = 0; i < 9, i++){
for(int j = 0; j < 9, j++){
ftime[k] = i;
ttime[k] = j;
k++;
}
}
Remember K.I.S.S.
Comments
this should fix it
#include <iostream>
using namespace std;
void printArray (int arg[], int length) {
for (int n=0; n<length; ++n)
cout << arg[n] << ' ';
cout << '\n';
}
int main()
{
int ftime[99];
int ttime[99];
for(int j=0; j < 99; j++)
{
ftime[j] = j/10;
ttime[j] = j%10;
}
cout << "Time: ";printArray(ftime,99);
cout << " ";printArray(ttime, 99);
return 0;
}
Comments
declare both as integers and use the following for loop
for(int i=0;i<100;i++);
{
ftime[i]=i/10;
ttime[i]=i%10;
}
Comments
#define MAX 99
int ftime [MAX+1]; // Includes 00 too
int ttime [MAX+1]; // Includes 00 too
for (int ctr = 0; ctr < MAX+1, ctr++) {
ftime[ctr] = floor(ctr/10);
ttime[ctr] = ctr % 10; // modulus oper
}
This may have syntax errors, sorry. Didn't have a c-compiler handy on this computer of mine.
Comments
lang-cpp