The below code accepts an integer and checks and prints if <5, or if divisible by 5, or if divisible by 3 or if divisible by both 3 and 5. but I want to put the code into infinite looping so that the console repeatedly asks me to enter an integer after printing the output. Here is my code so far:
import java.util.Scanner;
public class Q3c {
public static void main(String args[]) {
System.out.println("Enter an integer ");
Scanner input = new Scanner(System.in);
int n = input.nextInt();
if ((n%5 == 0) && (n%3 == 0)) {
System.out.println("The number " + n + " is divisible by 3 and 5");
}
else {
if(n%5 == 0) {
System.out.println(n + " is divisble by 5");
}
if(n%3 == 0) {
System.out.println(n + " is divisble by 3");
}
}
if (n < 5) {
System.out.println(n + "is <5");
}
input.close();
}
}
demo output:
Enter an integer 5
5 is divisibe by 5
Enter an integer
Malvon
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3 Answers 3
while(true) {
//do stuff
}
for(;;) {
//do stuff
}
do {
//stuff
}while(true);
All three of these are infinite loops. If you want to exit the infinite loop based on some user input (suppose 0), you can just add:
if(n == 0) {
break;
}
where ever you want your loop to end if they have entered 0. This code snippet works for all three infinite loop variations.
answered Dec 9, 2013 at 22:53
nhgrif
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Comments
while(true) {
//your code
//code to manage program exit.
}
or
for(;;) {
//your code
//code to manage program exit.
}
or
do {
//your code
//code to manage program exit.
}while(true);
answered Dec 9, 2013 at 22:56
umanganiello
7544 silver badges7 bronze badges
Comments
I'd suggest using else if constructs, in your case, just to simplify the code... Something like:
Scanner input=new Scanner(System.in);
while(true) {
System.out.println("Enter an integer ");
int n=input.nextInt();
if((n%5==0)&&(n%3==0)){
//stuff
} else if (n%5==0) {
//other stuff
} else if (n%3==0) {
//other
}
}
Comments
lang-java