I need help regarding insertion of array elements as objects into another array in Javascript. I have the following code:
tableLength = 3;
nyCourt = [];
oldArr = [Buy, String, Question]
for (var t = 0; t < tableLength; t++) {
nyCourt.push({});
for (var i = 0; i < OldArr.length; i++) {
nyCourt.Title = OldArr[i] ;
}
};
The code isnt working, I want output in the following format
[{Title:Buy },
{Title: String},
{Title: Question}]
But the output I get is this:
[{Title:Question },
{Title: Question},
{Title: Question}]
STT LCU
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"But the output I get is this" I don't think so, not with that code.T.J. Crowder– T.J. Crowder2013年10月30日 08:34:54 +00:00Commented Oct 30, 2013 at 8:34
3 Answers 3
This line:
nyCourt.Title = OldArr[i]
writes to the Title property on the nyCourt object (which is an array object), repeatedly in the loop. The last assignment wins.
But given what you've said you want your output to be, your code is over-complex. You only need one loop:
var nyCourt = [];
var oldArr = [Buy, String, Question];
for (var i = 0; i < oldArr.length; i++) {
nyCourt.push({Title: oldArr[i] });
}
Live Example (use Chrome or something else modern) | Source
Or as this is Node so we know we have map:
var oldArr = [Buy, String, Question];
var nyCourt = oldArr.map(function(entry) {
return {Title: entry};
});
answered Oct 30, 2013 at 8:34
T.J. Crowder
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3 Comments
T.J. Crowder
@Rajat: That makes no sense, given the output you've said you want. Why do you want two loops?
Akshat
Because that is an assignment :(
T.J. Crowder
@Rajat: Due respect, I think you've misunderstood the assignment. You either need two loops and the result you're supposed to achieve isn't what you've listed, or the result you've listed is correct and you shouldn't use two loops.
//this give the output you want
tableLength = 3;
nyCourt = [];
oldArr = ['Buy', 'String', 'Question'];
for (var t = 0; t < oldArr.length; t++) {
nyCourt.push({Title: oldArr[t]});
};
console.log(nyCourt);
Comments
place that push function inside the loop also change the code like this
for (var t = 0; t < tableLength; t++) {
for (var i = 0; i < OldArr.length; i++) {
nyCourt.push({"Title": oldArr[t]});
}
};
answered Oct 30, 2013 at 8:50
Arvin
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1 Comment
Akshat
Thanks Arviin for the help
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