5

So first... my directory structure..

---script/execute.py
 |
 L---helper---foo.py
 L-----bar.py
 L--- __init__.py

Now, execute.py calls both foo and bar .py as

from helper.foo import some_func

I am trying to run this as:

python script/execute.py

But I am getting this import error

 from helper.foo import some_func
 Import error: No module named helper??

What am I missing (note that there is no init inside script folder??)?

Thanks

asked Oct 17, 2013 at 20:22
7
  • 3
    looks like helper is not on same level as execute Commented Oct 17, 2013 at 20:27
  • @cox: my bad.. but helper and execute are on same level Commented Oct 17, 2013 at 20:30
  • @cox: but i am executing from a level up.. Commented Oct 17, 2013 at 20:30
  • 1
    If you run python execute.py, do you have the same problem? Commented Oct 17, 2013 at 20:35
  • 1
    Works for me. execute.py and the helper module are really in the same directory? Commented Oct 17, 2013 at 20:35

1 Answer 1

2

You should check out http://docs.python.org/2/tutorial/modules.html#packages

The "too long, didn't read" of it is that you need to have a file called __init__.py in your helper directory, e.g.,

$ touch helper/__init__.py

The file can also contain Python code, but in the simplest form an empty file is ok.

sth
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answered Oct 17, 2013 at 21:05
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1 Comment

The directory structure at the top of the question clearly shows that helper already contains an __init__.py.

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