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Im trying to do a simple check if there is 3 specific value in a string. If there is, the statement should return nothing, instead of save.

Here is my code, but I think the syntax is wrong:

if not ('2239687' or '2238484' or '2239440') in user_id:
 #The user is not admin, save the user
 web_user.save()

To elaborate, I want it to test if user_id is "2239687" or "2238484" or "2239440" (and not, for example, "002239440"). If the user_id is one of those three values (and ONLY those three values), the statement should return false.

georg
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asked Mar 26, 2013 at 8:35
6
  • If you wanna see what's happening: diveintopython.net/power_of_introspection/and_or.html Commented Mar 26, 2013 at 8:40
  • To clarify, 1) "user_id" is a string, right? 2) should it return True if user_id = 99922396879999? Commented Mar 26, 2013 at 9:07
  • Yes user_id should be a string. All other values should return True, but these three values should return False. Is there some way I can test if the user_id is a string or not? Commented Mar 26, 2013 at 9:20
  • @Garreth00: now I'm confused. Are you testing if user_id contains "2239687" (or 2238484 or 2239440) - as in "99922396879999" - or if it's equal to "2239687" (or 2238484 or 2239440)? Commented Mar 26, 2013 at 9:24
  • @thg435: I want it to test if user_id is "2239687" or "2238484" or "2239440" (and not "002239440") If the user_id is one of those three values (and ONLY those three values), the statement should return false Commented Mar 26, 2013 at 9:33

3 Answers 3

2 
if not any(x in user_id for x in ('2239687', '2238484', '2239440')):
 #The user is not admin, save the user
 web_user.save()

This checks whether none of the three string is present within user_id.

answered Mar 26, 2013 at 8:46
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2

One more option:

if not any(idx in user_id for idx in ('2239687' ,'2238484' , '2239440')):
 # do something
answered Mar 26, 2013 at 8:40

4 Comments

This should not be used in this case
@jamylak yes, maybe you are right, then just a case to know that 'any' function exists
@glglgl i know - but each ohe us can only suppose what type of comparison he need - the option here is 'any' function not a comparison type
id is a built-in function. Don't use it as a variable name.
1

Try like this

if user_id not in ('2239687' ,'2238484' , '2239440'):

Or

if not user_id in ('2239687' ,'2238484' , '2239440'):
answered Mar 26, 2013 at 8:36

3 Comments

This seems right, but the "save" does still gets executed me (I'm 2239687).
@Garreth00 str(2239687) not in ('2239687' ,'2238484' , '2239440') try like this,
Correct me but i always thought that 'not user_id in ('2239687' ,'2238484' , '2239440'):' is not very pythonic?

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