While loop not breaking

The problem is that raw_input returns a string. You're comparing a string with an integer which you can do in python 2.x (In python 3, this sort of comparison raises a TypeError), but the result is apparently always False. To make this work you probably want something like var=int(raw_input('Enter the block number'))

From the documentation:

objects of different types always compare unequal, and are ordered consistently but arbitrarily.

You're needlessly checking var twice, and you're trying to compare int and str (because raw_input returns a string), which doesn't work right. Try this:

var=0
while True:
 var=int(raw_input('Enter the block number '))
 if (var >=1 and var<=100):
 print '\nBlock Number : ',var 
 break
 else:
 print 'ERROR!!! Enter again.'

You should convert your string to int.

var=0
while (var <1 or var>100):
 # I changed here
 var=int(raw_input('Enter the block number '))
 if (var >=1 and var<=100):
 print '\nBlock Number : ',var 
 else:
 print 'ERROR!!! Enter again.'

You're running into an issue that strings (as returned by raw_input) are always greater than integers:

>>> "25" > 100
True

You need to convert your input to an integer first:

var = int(raw_input("Enter the block number "))

Of course, you'll want to be resilient in the face of bad input, so you'll probably want to wrap the whole thing in a try block.

hello you need to enter "break" and also var should be an integer, see below

while True:
var=int(raw_input('Enter the block number '))
if (var >=1 and var<=100):
 print '\nBlock Number : ',var
 break
else:
 print 'ERROR!!! Enter again.'
 continue

hope this helps

• python
• while-loop