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I am working with selenium in python. Currently, I have written a script that opens a new tab from one of the search results of Google. The associated code is as follows:

from time import sleep
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.wait import WebDriverWait
from python_file.crawler.browser import Browser
browser = Browser(0).getBrowser()
browser.get('https://www.google.com?q=python#q=python')
first_result = WebDriverWait(browser, 15).until(lambda browser: browser.find_element_by_class_name('rc'))
first_link = first_result.find_element_by_tag_name('a')
# Save the window opener (current window)
main_window = browser.current_window_handle
# Open the link in a new window by sending key strokes on the element
first_link.send_keys(Keys.SHIFT + Keys.RETURN)
# Get windows list and put focus on new window (which is on the 1st index in the list)
windows = browser.window_handles
print("opened windows length: ", len(windows))
browser.switch_to.window(windows[1])
# do whatever you have to do on this page, we will just got to sleep for now
sleep(3)
# Close current window
browser.find_element_by_tag_name('body').send_keys(Keys.CONTROL + 'w')

But I am getting an exception in the following line.

windows = browser.window_handles
print("opened windows length: ", len(windows))
browser.switch_to.window(windows[1])

As no of the window is 2, so I think windows[1] are valid. Why am I getting this exception?

Traceback (most recent call last):
 File "<input>", line 1, in <module>
 File "/home/sultan/Desktop/pycharm-2019年3月1日/plugins/python/helpers/pydev/_pydev_bundle/pydev_umd.py", line 197, in runfile
 pydev_imports.execfile(filename, global_vars, local_vars) # execute the script
 File "/home/sultan/Desktop/pycharm-2019年3月1日/plugins/python/helpers/pydev/_pydev_imps/_pydev_execfile.py", line 18, in execfile
 exec(compile(contents+"\n", file, 'exec'), glob, loc)
 File "/home/sultan/PycharmProjects/Gender_Identification_Admin/python_file/crawler/apatoto/sustho.py", line 20, in <module>
 browser.switch_to.window(windows[1])
IndexError: list index out of range
# Put focus back on main window
browser.switch_to.window(main_window)
IAmMilinPatel
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asked Mar 1, 2020 at 17:50
4
  • If you found an answer you can also add it :) Commented Mar 1, 2020 at 19:25
  • Are u sure browser is opening in new tab , then add a wait before getting window_handles Commented Mar 1, 2020 at 19:44
  • Print windows and see if it actually have two values Commented Mar 1, 2020 at 19:47
  • First verify that actually new tab exist, i hope may this help you stackoverflow.com/questions/12729265/… Commented Mar 2, 2020 at 11:24

1 Answer 1

2

Your code works perfectly fine, I just changed the closed browser part and browser creation part:

from time import sleep
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.wait import WebDriverWait
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
browser = webdriver.Chrome()
browser.get('https://www.google.com?q=python#q=python')
first_result = WebDriverWait(browser, 15).until(lambda browser: browser.find_element_by_class_name('rc'))
first_link = first_result.find_element_by_tag_name('a')
# Save the window opener (current window)
main_window = browser.current_window_handle
# Open the link in a new window by sending key strokes on the element
first_link.send_keys(Keys.SHIFT + Keys.RETURN)
# Get windows list and put focus on new window (which is on the 1st index in the list)
windows = browser.window_handles
print("opened windows length: ", len(windows))
browser.switch_to.window(windows[1])
# do whatever you have to do on this page, we will just got to sleep for now
sleep(3)
# Close current window
browser.close()
answered Mar 2, 2020 at 8:56

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