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Hi, I'm trying to use a custom font that is set dynamically at runtime, if available. (I don't want this font to be the default in the config file.) But matplotlib keeps defaulting to the generic sans-serif font if I include that as an option later in the font family list. In the process of troubleshooting, I found there was a commit which already addressed this issue (https://github.com/matplotlib/matplotlib/commit/314a0cf), although unfortunately it didn't solve it in my particular case, when the font being scored is first in the rcParams font alias list. Seems like it could be an easy fix for someone familiar with the scoring algorithm. I don't see quite what the expected scores *should* be (the docstring for that function looks to be out of sync) but it shouldn't be 0 for default fonts not explicitly named first in the family list. I'll put this in the bug tracker and try to workaround for now. Thanks, cw
Your code example is incomplete. Even if I add in the typical imports and "fig, ax = plt.subplots()" and "plt.show()", The x tick labels aren't rotated, and I certainly don't have too many tick labels. Could you provide a complete working example that demonstrate the problem? Ben Root On Wed, Jul 8, 2015 at 9:15 AM, manik971 <nec...@ho...> wrote: > <code> > date_range = (735599.0, 735745.0) > x = (735610.5, 735647.0, 735647.5, 735648.5, 735669.0, 735699.0, 735701.5, > 735702.5, 735709.5, 735725.5, 735728.5, 735735.5, 735736.0) > y = (227891.25361545716, 205090.4880046467, 208352.59317388065, > 175462.99296699322, 98209.836461969651, 275063.37219361769, > 219456.93600708069, 230731.12613806152, 209043.19805037521, > 218297.51486296533, 208036.88967207001, 206311.71988471842, > 216036.56824433553) > y0 = 218206.79192 > x_after = (735610.5, 735647.0, 735647.5, 735701.5, 735702.5, 735709.5, > 735725.5, 735728.5, 735735.5, 735736.0) > y_after = (227891.25361545716, 205090.4880046467, 208352.59317388065, > 219456.93600708069, 230731.12613806152, 209043.19805037521, > 218297.51486296533, 208036.88967207001, 206311.71988471842, > 216036.56824433553) > ax.plot_date(x, numpy.array(y) / y0, color='r', xdate=True, marker='x') > linex = -39.1175584541 > liney = 28993493.5251 > > ax.set_xlim(date_range) > steps = list(ax.get_xlim()) > steps.append(steps[-1] + 2) > steps = [steps[0] - 2] + steps > ax.plot(steps, numpy.array([linex * a + liney for a in steps]) / y0, > color='b') > </code> > > > > -- > View this message in context: > http://matplotlib.1069221.n5.nabble.com/Plot-Too-many-ticks-on-X-axe-tp45893p45894.html > Sent from the matplotlib - users mailing list archive at Nabble.com. > > > ------------------------------------------------------------------------------ > Don't Limit Your Business. Reach for the Cloud. > GigeNET's Cloud Solutions provide you with the tools and support that > you need to offload your IT needs and focus on growing your business. > Configured For All Businesses. Start Your Cloud Today. > https://www.gigenetcloud.com/ > _______________________________________________ > Matplotlib-users mailing list > Mat...@li... > https://lists.sourceforge.net/lists/listinfo/matplotlib-users >
<code> date_range = (735599.0, 735745.0) x = (735610.5, 735647.0, 735647.5, 735648.5, 735669.0, 735699.0, 735701.5, 735702.5, 735709.5, 735725.5, 735728.5, 735735.5, 735736.0) y = (227891.25361545716, 205090.4880046467, 208352.59317388065, 175462.99296699322, 98209.836461969651, 275063.37219361769, 219456.93600708069, 230731.12613806152, 209043.19805037521, 218297.51486296533, 208036.88967207001, 206311.71988471842, 216036.56824433553) y0 = 218206.79192 x_after = (735610.5, 735647.0, 735647.5, 735701.5, 735702.5, 735709.5, 735725.5, 735728.5, 735735.5, 735736.0) y_after = (227891.25361545716, 205090.4880046467, 208352.59317388065, 219456.93600708069, 230731.12613806152, 209043.19805037521, 218297.51486296533, 208036.88967207001, 206311.71988471842, 216036.56824433553) ax.plot_date(x, numpy.array(y) / y0, color='r', xdate=True, marker='x') linex = -39.1175584541 liney = 28993493.5251 ax.set_xlim(date_range) steps = list(ax.get_xlim()) steps.append(steps[-1] + 2) steps = [steps[0] - 2] + steps ax.plot(steps, numpy.array([linex * a + liney for a in steps]) / y0, color='b') </code> -- View this message in context: http://matplotlib.1069221.n5.nabble.com/Plot-Too-many-ticks-on-X-axe-tp45893p45894.html Sent from the matplotlib - users mailing list archive at Nabble.com.
Hello, The first loaded plot have too many ticks on X axe (see image01). <http://matplotlib.1069221.n5.nabble.com/file/n45893/help-01.jpg> If I use the zoom action on X axe, the plot is now well loaded. <http://matplotlib.1069221.n5.nabble.com/file/n45893/help-02.jpg> Can you give me some advise where I can search because The Plot constructor parameters seems good. Thank you for your help. Manuel -- View this message in context: http://matplotlib.1069221.n5.nabble.com/Plot-Too-many-ticks-on-X-axe-tp45893.html Sent from the matplotlib - users mailing list archive at Nabble.com.