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I finally committed this fix. -- Jouni K. Seppänen http://www.iki.fi/jks
Hello list, I am trying to run the "histogram_demo_extended.py" on my mac 10.5. I installed matplotlib through the scisoft package. The normal hist command works fine but when I tried to use "align" or "histtype" keyward I get this kind of error: [Macintosh-2:~/optional/examples/pylab_examples] nino% ./histogram_demo_extended.py Traceback (most recent call last): File "./histogram_demo_extended.py", line 15, in <module> n, bins, patches = P.hist(x, 50, normed=1, histtype='stepfilled') File "/scisoft/i386/library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/site-packages/matplotlib/pyplot.py", line 1633, in hist ret = gca().hist(*args, **kwargs) File "/scisoft/i386/library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/site-packages/matplotlib/axes.py", line 5064, in hist p.update(kwargs) File "/scisoft/i386/library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/site-packages/matplotlib/artist.py", line 394, in update raise AttributeError('Unknown property %s'%k) AttributeError: Unknown property histtype Can someone give me any advice? Thanks a lot in advance. nino -- Antonino Cucchiara PhD candidate Department of Astronomy&Astrophysics Penn State University website: www.astro.psu.edu/~cucchiara/
Hi, How can I plot numbers on the x and y axes in scientific notation? I have very large values on the y axis which I'd like to show as 1e9 and not 1 followed by 9 zeros.
Hi, Thanks a lot to all of you for your help. This looks very promising. I will test it on Monday. Regards, Marjolaine. >>> Michael Droettboom <md...@st...> 09/05/08 7:54 PM >>> You could do something like: def bitget(value, bit_number): return (value & (1 << bit_number)) != 0 which will return True or False for the given bit number, and this function works on numpy arrays. (Bits are numbered base-0 -- I don't know if that matches matlab). Hope that helps, Mike Marjolaine Rouault wrote: > Hi, > > I was wondering if python has the equivalent of the matlab bitget.m function. > > I have a large 2 dimensional variable of type uint32 which I must convert to binaries and then find if bit 23 of the binary for each point is 0 or 1. The matlab bitget function is ideal for that but I can't find much in python. The only thing I found was binary_repr which converts to a sting and can only be used for 1 point at a time. > > Any suggestions? > > Thanks, Marjolaine. > > -- Michael Droettboom Science Software Branch Operations and Engineering Division Space Telescope Science Institute Operated by AURA for NASA -- This message is subject to the CSIR's copyright terms and conditions, e-mail legal notice, and implemented Open Document Format (ODF) standard. The full disclaimer details can be found at http://www.csir.co.za/disclaimer.html. This message has been scanned for viruses and dangerous content by MailScanner, and is believed to be clean. MailScanner thanks Transtec Computers for their support.
dmitrey wrote: > Eric Firing wrote: >> dmitrey wrote: >>> hi all, >>> matplotlib says it's similar to MATLAB's plot tool, however, using >>> plot(..., 'p') plots pentagram instead of star. It makes my (Python >>> scikits.openopt) graphic output of numerical convergence look uglier >>> than MATLAB version. >>> >>> So is plotting a star intended to be ever implemented? >> Dmitrey, >> >> It was easy, so I added a 5-point star to the set of available markers >> in svn. Use plot(..., '*'). 'p' was already taken, and '*' seems >> more mnemonic--I would never think of 'p' as indicating a star. >> >> Eric > Thank you, currently I'm using scatter (it will take a time while all > users will have the matplotlib version with '*' available). > > There is unclear parameter in scatter docstring, could you explain what > does it mean: > > *s*: > size in points^2. It is a scalar or an array of the same > length as *x* and *y*. > > so what does it mean "size in points^2"? It means the area of the circle circumscribing the marker, with that area measured in units of points squared. The strange choice of s as a measure of area instead of radius or diameter is for compatibility with Matlab. Eric > > Regards, D.
Ah, Ich verstehe now. I'll try RGBA-ing it; in the meantime, let me know if the colormapping conversion gets changed to 32 bit. Thanks again! DG --- On Sat, 9/6/08, Eric Firing <ef...@ha...> wrote: > From: Eric Firing <ef...@ha...> > Subject: Re: [Matplotlib-users] imshow size limitations? > To: d_l...@ya... > Cc: mat...@li... > Date: Saturday, September 6, 2008, 3:13 PM > David Goldsmith wrote: > > Thanks, Eric! > > > > --- On Sat, 9/6/08, Eric Firing > <ef...@ha...> wrote: > > > > -- snip OP -- > > > >> It looks to me like you simply ran out of > memory--this is > >> not an imshow > >> problem as such. Your array is about 1e8 > elements, and as > >> floats that > >> would be close to a GB--just for that array alone. > Do you > > > > Well, I anticipated that, so I do initialize the > storage for the numpy array as numpy.uint8 and have > confirmed that the data in the array returned by the > function which creates it remains numpy.uint8, so it should > "only" be ~100MB (indeed, the .na file into which > I tofile it is 85,430 KB, just as it should be for a 10800 x > 8100 array of uint8 elements). And the ax.imshow statement > doesn't (directly) cause the crash (but I don't know > that it isn't making either a float copy or an in-place > conversion of the array). So, AFAIK, right up until the > statement: > > > > canvas.print_figure('HiResHex') > > > > the data being imaged are all numpy.uint8 type. > > Yes, but it looks to me like they are still getting > color-mapped, and > this requires conversion to numpy.float. This may be a bad > aspect of > the mpl design, but it is quite deeply embedded. I suspect > the best we > could do would be to use float32 instead of float64; > certainly for color > mapping one does not need 64 bits. > > Using numpy.uint8 helps only if you are specifying RGBA > directly, > bypassing the colormapping. > > > > >> really need > >> all that resolution? > > > > Well, there's the rub: I fancy myself a fractal > "artist" and I have > > access to an HP DesignJet 500ps plotter with a maximum > resolution of > > 1200 x 600 dpi. For the size images I'm trying to > make (I'm hoping to go > > even bigger than 36" x 27", but I figured > that as a good starting point) > > even I regard _that_ resolution as too much - I was > thinking of 300 x > > 300 dpi (which is its "normal" resolution) > as certainly worthy of giving > > a try. :-) > > >> If you do, you will probably have to > >> get a much > >> more capable machine. > > > > Possible, but I was hoping to generate at least one > "proof" first to determine how hard I'd need > to try. > > > >> Otherwise, you need to knock down > >> the size of > >> that array before trying to plot or otherwise > manipulate > >> it. > > > > Forgive me, but I'd like a more detailed > explanation as to why: I > > have > > ample (~35 GB, just on my built-in disc, much more > than that on external > > discs) harddisc space - isn't there some way to > leverage that? > > I don't know enough about virtual memory > implementations--especially on > Win or Mac--to say. In practice, I suspect you would find > that as soon > as you are doing major swapping during a calculation, you > will thrash > the disk until you run out of patience. > > > >> With respect to imshow, probably you can get it to > handle > >> larger images > > > > Again, imshow doesn't appear to be the culprit > (contrary to my > > original subject line), rather it would appear to be > > canvas.print_figure. (While I'm on the subject of > canvas.print_figure, > > isn't there some way for MPL to "splash" > the image directly to the > > screen, without first having to write to a file? I > didn't ask this > > before because I did eventually want to write the > image to a file, but I > > would prefer to do so only after I've had a look > at it.) > > It is imshow in the sense that most of the action in mpl > doesn't happen > when you call imshow or plot or whatever--they just set > things up. The > real work is done in the backend when you display with > show() or write > to a file. > > > >> if you feed them in as NxMx4 numpy.uint8 RGBA > arrays--but I > >> doubt this > >> is going to be enough, or the right approach, for > your > >> present situation. > > > > Right: I don't see how that would be better than > having a single 8 > > bit > > datum at each point w/ color being determined from a > color map (which is > > how I'd prefer to do it anyway). > > The way it is better is that it avoids a major operation, > including the > generation of the double-precision array. The rgba array > can go > straight to agg. > > Eric > > > > Thanks again, > > > > DG > >> Eric > >> > >>> Platform Details: MPL 0.91.2 (sorry, I > didn't > >> realize I was running such an old version, maybe I > just need > >> to upgrade?), Python 2.5.2, Windows XP 2002 SP3, > 504MB > >> physical RAM, 1294MB VM Page size (1000MB init., > 5000MB max) > >>> Thanks! > >>> > >>> DG