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Showing 5 results of 5

From: Christian M. <mee...@im...> - 2009年09月06日 19:25:13
Hi,
Let me reformulate my question: Is there a way to put ticklabels not
beside, but between ticks (centered between)?
TIA
Christian
On Fri, 2009年09月04日 at 10:53 +0200, Christian Meesters wrote:
> Hi,
> 
> I have the following code:
> 
> pylab.pcolormesh(data, multialignment='center')
> xlocs, xlabels = pylab.xticks(range(0, data.shape[1]+1), xlabels)
> pylab.setp(xlabels, 'rotation', 70)
> pylab.colorbar()
> pylab.show()
> 
> where data is a 2D numpy array containing some masked values and
> 'xlabels' is - originally - a list of strings for the xlabels.
> 
> This gives me two problems:
> - The "column" on the right is shown as blank, although this column has
> valid data and
> - the labels aren't placed below the center of a field, but below the
> xticks. I would like to have them centered, below a field, as the ticks
> are merely separators and not associated with any unit.
> 
> TIA
> Christian
> 
> 
> ------------------------------------------------------------------------------
> Let Crystal Reports handle the reporting - Free Crystal Reports 2008 30-Day 
> trial. Simplify your report design, integration and deployment - and focus on 
> what you do best, core application coding. Discover what's new with 
> Crystal Reports now. http://p.sf.net/sfu/bobj-july
> _______________________________________________
> Matplotlib-users mailing list
> Mat...@li...
> https://lists.sourceforge.net/lists/listinfo/matplotlib-users
From: tva <tv...@br...> - 2009年09月06日 19:06:20
Hi all
with matplotlib 0.98.5.3 this script will draw new lines as the scrips is
running:
from pylab import *
x = arange(0,2*pi,0.01) 
for i in arange(1,20):
	
	y=sin(x+i)
	plot(x,y) # update the data
	show()
with matplotlib 0.99, the exact same script runs to the end without plotting
and then plots all the lines. This is just a trivial example but for some
applications it is useful to monitor the evolution of curves as the script
is running - allows me to update parameters if something diverges.
Any idea why there is such a difference between 0.98.5.3 and 0.99 ?? 
-- 
View this message in context: http://www.nabble.com/cannot-plot-in-loops-with-matplotlib-0.99.-0.98-works-fine-tp25320454p25320454.html
Sent from the matplotlib - users mailing list archive at Nabble.com.
From: Sandro T. <mo...@de...> - 2009年09月06日 09:35:53
On Sun, Sep 6, 2009 at 11:11, Tsviki Hirsh<tsv...@gm...> wrote:
> Dear list,
> I were trying to install matplotlib 0.99 on my ubuntu interpid, I had
> previously installed and extensively used the great 0.98 version.
> There is not seem to be any .deb file for 0.99 on ubuntu.packages site yet,
yes, we know and we are working on it (I'm holding this back a bit due
to other committements, and because ubuntu is in feature freeze for
the upcoming release).
> so I tried to untar and install the source file.
> The installation went smoothly, and when I print the value of __version__
> from matplotlib within ipython, it says "0.99".
> However, when I try to import axes3d from matplotlib, it shouts at me that
> this module is disable in matplotlib 0.98 (!).
> So the question is, should I uninstall 0.98 before compiling the 0.99 source
> or what?
well, this is hardly a question for this list (I see it more for
ubuntu forums), but yes, either you remove python-matplotlib package
(it's and 'apt-get update' away to reinstall if needed), or you play
with sys.path, PYTHONPATH, and so on. For personal packages, you can
also install them into a directory in ~ (using the --root and --prefix
when setup.py install).
Regards,
-- 
Sandro Tosi (aka morph, morpheus, matrixhasu)
My website: http://matrixhasu.altervista.org/
Me at Debian: http://wiki.debian.org/SandroTosi
From: Tsviki H. <tsv...@gm...> - 2009年09月06日 09:11:42
Dear list,I were trying to install matplotlib 0.99 on my ubuntu interpid, I
had previously installed and extensively used the great 0.98 version.
There is not seem to be any .deb file for 0.99 on ubuntu.packages site yet,
so I tried to untar and install the source file.
The installation went smoothly, and when I print the value of __version__
from matplotlib within ipython, it says "0.99".
However, when I try to import axes3d from matplotlib, it shouts at me that
this module is disable in matplotlib 0.98 (!).
So the question is, should I uninstall 0.98 before compiling the 0.99 source
or what?
I thank you for your help and all those intersting conversations running on
the list.
Cheers,
Tsviki Hirsh
tsv...@gm...
From: nbv4 <cp3...@oh...> - 2009年09月06日 02:12:17
Jouni K. Seppänen wrote:
> 
> nbv4 <cp3...@oh...> writes:
> 
>> [1,0,0,0,2,3,2,1,0,0,0,2,2,1,3,0,0,3...]
>>
>> [...] I want to take this data and display it in a linegraph
>> as if it were this data:
>>
>> [1,1,1,1,3,5,7,8,8,8,10,12,13,16,16,16,19,...]
> 
> You can use numpy.cumsum to transform your data. For example, in ipython
> -pylab:
> 
> In [4]: x = [1,0,0,0,2,3,2,1,0,0,0,2,2,1,3,0,0,3]
> 
> In [5]: cumsum(x)
> Out[5]: 
> array([ 1, 1, 1, 1, 3, 6, 8, 9, 9, 9, 9, 11, 13, 14, 17, 17, 17,
> 20])
> 
> In [6]: plot(cumsum(x))
> Out[6]: [<matplotlib.lines.Line2D object at 0xa945070>]
> 
> -- 
> Jouni K. Seppänen
> http://www.iki.fi/jks
> 
> 
> ------------------------------------------------------------------------------
> Let Crystal Reports handle the reporting - Free Crystal Reports 2008
> 30-Day 
> trial. Simplify your report design, integration and deployment - and focus
> on 
> what you do best, core application coding. Discover what's new with 
> Crystal Reports now. http://p.sf.net/sfu/bobj-july
> _______________________________________________
> Matplotlib-users mailing list
> Mat...@li...
> https://lists.sourceforge.net/lists/listinfo/matplotlib-users
> 
> 
Thats exactly it, thanks!
-- 
View this message in context: http://www.nabble.com/How-to-do-accumulation-plots-with-matplotlib-tp25304056p25313944.html
Sent from the matplotlib - users mailing list archive at Nabble.com.

Showing 5 results of 5

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