matplotlib-users Mailing List for matplotlib

Fixed by switching the backend from WXAgg to MacOSX.
starz1010101 wrote:
> 
> I can't force pyplot to draw in the middle a function. For example, this
> function does not plot the sine before the user prompt, only after the
> entire function executes:
> 
> import matplotlib.pyplot as plt
> import numpy as np
> 
> def plot_now():
> plt.ion()
> plt.figure()
> x = 2*np.pi*np.linspace(0.0, 1.0, 100)
> plt.plot( x, np.sin(x) )
> plt.draw()
> plt.draw()
> q = raw_input( 'anything: ')
> 
> I'm using the enthought python distribution for mac in ipython. 
> 
> 
> 
> 
> 
-- 
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On 10/25/2010 9:23 AM, Stan West wrote:
> markerline.set_zorder(stemlines[0].get_zorder() + 0.1)
Thanks.
Now I can easily get what I want.
But back to the underlying question:
do people really prefer the stems to overlay the markers?
I.e., are the ``stem`` defaults possibly incorrect?
Thanks,
Alan

On Fri, Nov 5, 2010 at 7:12 AM, John M. Densmore (Cont, ARL/WMRD)
<joh...@us...> wrote:
> Hi All,
> I have multiple figures set up at the start of my code. through out the
> script I add data to the plots and at the end I would like to set all
> the figure parameters, like xlim, ylim, legend etc. But I can not figure
> out how to do it. Eample code
>
> fig1 = plt.figure(1)
> ax1 = fig1.add_subplot(111)
>
>
> fig2 = plt.figure(2)
> ax2 = fig2.add_subplot(111)
>
>
> fig3 = plt.figure(3)
> ax3 = fig3.add_subplot(111)
>
> ax1.plot(...)
> ax2.plot(...)
> ax3.plot(...)
>
>
> ax1.plot(...)
> ax2.plot(...)
> ax3.plot(...)
>
> # set the x and y lim <- how do I do this?
ax1.set_xlim(xmin, xmax)
ax1.set_ylim(ymin, ymax)
...
Ryan
-- 
Ryan May
Graduate Research Assistant
School of Meteorology
University of Oklahoma

A small suggestion to the examples ...
I really like the new subplot mechanism, so I tried it:
fig, (ax1, ax2, ax3, ax4) = plt.subplots(2, 2, sharex=True, sharey=True)
And it actually gave me the following error:
Traceback (most recent call last):
 File "tes.py", line 21, in <module>
 f, (ax1, ax2, ax3, ax4) = subplots(2, 2, sharey=True)
ValueError: need more than 2 values to unpack
I got over with with a small modification:
f, ((ax1,ax2),(ax3,ax4)) = subplots(2, 2, sharey=True)
Which now worked !
Cheers,
-- 
Oz Nahum
Graduate Student
Zentrum für Angewandte Geologie
Universität Tübingen
---
Imagine there's no countries
it isn't hard to do
Nothing to kill or die for
And no religion too
Imagine all the people
Living life in peace

Hi,
The best way to do this is to use a generator:
import itertools
import matplotlib.pyplot as plt
import numpy as np
def _ncycle(iterable,n):
 """
 Method to create a generator from an iterable. It keeps the
 current position of the iterable in memory. Each time the
 next() method for the iterable is called, it will return the
 next item. If there are no more items, it will cycle to the
 first item.
 """
 for item in itertools.cycle(iterable):
 yield item
colors = _ncycle(('r','g','b','c','y','m','k'),1)
markers = _ncycle(('o','s','v'),1)
n = 20
fig = plt.figure()
ax = fig.add_subplot(111)
for i in range(n):
 x = np.arange(0,10)
 y = np.sin(x)+i-n/2
 c = colors.next()
 if c == 'r':
 marker = markers.next()
 ax.plot(x,y,c=c,marker=marker)
plt.show()
On Fri, Nov 5, 2010 at 8:29 AM, Neal Becker <ndb...@gm...> wrote:
> How can I automatically cycle through distinctive line markers?
>
> I want a semilog plot, composed of a number of lines. Each line should
> have
> a different color and marker.
>
> Cycling through the colors is automatic, but not the markers.
>
> BTW, shouldn't this behavior be the default? I would just like to say
> markers=True and get this behavior.
>
>
>
> ------------------------------------------------------------------------------
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-- 
Aman Thakral
B.Eng & Biosci, M.Eng Design

Hi All,
I have multiple figures set up at the start of my code. through out the 
script I add data to the plots and at the end I would like to set all 
the figure parameters, like xlim, ylim, legend etc. But I can not figure 
out how to do it. Eample code
fig1 = plt.figure(1)
ax1 = fig1.add_subplot(111)
fig2 = plt.figure(2)
ax2 = fig2.add_subplot(111)
fig3 = plt.figure(3)
ax3 = fig3.add_subplot(111)
ax1.plot(...)
ax2.plot(...)
ax3.plot(...)
ax1.plot(...)
ax2.plot(...)
ax3.plot(...)
# set the x and y lim <- how do I do this?
plt.show()
Thanks

How can I automatically cycle through distinctive line markers?
I want a semilog plot, composed of a number of lines. Each line should have 
a different color and marker.
Cycling through the colors is automatic, but not the markers.
BTW, shouldn't this behavior be the default? I would just like to say
markers=True and get this behavior.

On 5 November 2010 14:05, Scott Sinclair <sco...@gm...> wrote:
> You probably want imshow, pcolor, pcolormash or matshow
I meant pcolormesh...

On 5 November 2010 13:33, Daniele Nicolodi <da...@gr...> wrote:
> I would like to plot an x, y, z table so that each region of the plot
> area defined by the coordinates (x, y) corresponds a color given by the
> value of z. I suppose this is a kind of basic functionality, but I'm
> unable to find the right function into matplotlib API.
You probably want imshow, pcolor, pcolormash or matshow
http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.imshow
http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.pcolor
http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.pcolormesh
http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.matshow
There's a basic example of using imshow here:
http://matplotlib.sourceforge.net/examples/pylab_examples/image_demo.html
Cheers,
Scott

Clever folks,
Is there an algorithm, or known method to extract a subset of one grid
to match another. I have two grids, one nested, the other global. In
general they are regular lat/lon grids. Also, in general they are 0.5
degree lat/lon. However, I would like to make this as general as
possible.
What I am trying to accomplish is the following:
A) to have a function where I pass the two grids and meta data about
the grids (lon0, lat0, dx, numx, dy, numy, etc). Then, a subsection of
the global grid is returned that matches the nested grid.
B) in a more general case, I may have to define a regrid function so
that the subset of the global grid could match the nested grid.
Suggestions?

Hello, I have a really dummy question.
I would like to plot an x, y, z table so that each region of the plot
area defined by the coordinates (x, y) corresponds a color given by the
value of z. I suppose this is a kind of basic functionality, but I'm
unable to find the right function into matplotlib API.
Thank you. Cheers,
-- 
Daniele

Hi!
I try to plot some interpolated data on a map and get an error saying
there are too many indices. When I use contour in matplotlib without
basemap I don't get the error. Also the map without a contour plot on it
works. Maybe some of you know what I do wrong?
Here is my code:
-------------
import numpy as np
import matplotlib.pyplot as plt
from matplotlib.mlab import griddata
from mpl_toolkits.basemap import Basemap
 
yi = np.linspace(min(Lat),max(Lat),100)
xi = np.linspace(min(Lon),max(Lon),50)
lon,lat,var = np.array(Lon), np.array(Lat), np.array(Var)
zi = griddata(lon,lat,var,xi,yi)
map = Basemap(projection='cyl', llcrnrlat=67, urcrnrlat=73,\
 llcrnrlon=4, urcrnrlon=20, resolution='h')
 
map.drawcoastlines()
map.drawmeridians(np.arange(0,360,1))
map.drawparallels(np.arange(-90,90,1))
xlon, ylat = map(xi,yi)
cs = map.contour(xlon,ylat,zi)
plt.show()
---------------
and this is the error message:
cs = map.contour(xlon,ylat,zi)
File
"/usr/local/lib/python2.6/dist-packages/mpl_toolkits/basemap/__init__.py",
line 2820, in contour
 xx = x[x.shape[0]/2,:]
IndexError: too many indices
Any help appreciated!
Sünnje