matplotlib-users Mailing List for matplotlib

Am 2015年03月27日 um 15:01 schrieb Sappy85:
> Hi all,
>
> tried to plot a streamline with matplotlib. So far it work's.
> But my question: Is there a possibility to avoid the gaps in the streamlines
> (see my picture)?
>
> <http://matplotlib.1069221.n5.nabble.com/file/n45276/ff850_0.png>
Are you sure your flow is non divergent? Otherwise sinks and sources of 
streamlines are quite natural. If your flow is divergence free I I 
frankly admit that I have no idea how to solve the problem with the 
(then) spurious gaps.
Regards, Foehn
>
> Regards
> Sappy85
>
>
>
>
>
> --
> View this message in context: http://matplotlib.1069221.n5.nabble.com/matplotlib-basemap-streamlines-plot-tp45276.html
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>
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Hi,
For those of you following the trials and tribulations of moi,
I hacked the solution. The assignment is:
x0 = [ [-1.0,0.0,0.5] ]
I printed the orig x0. Printed mine. Noticed mine was missing
a set of brackets. Tried it. Success!
--Prahas
On Sun, Mar 29, 2015 at 10:07 AM, Prahas David Nafissian <
pra...@gm...> wrote:
>
> Hi Mat-Plotters,
>
> I'm trying to modify the below code so that I can
> set the initial conditions to (-1,0,0.5).
>
> The code below randomly sets the initial conditions:
>
> **************
>
> # I changed the equation -- it's not Lorenz.
>
> N_trajectories = 1
>
> def lorentz_deriv((x, y, z), t0, aa=1.1, yy=0.87):
> """Compute the time-derivative of a Lorentz system."""
> return [y*(z-1+x*x)+yy*x, x*(3*z+1-x*x)+yy*y, -2*z*(aa+x*y)]
>
> # Choose random starting points, uniformly distributed from -15 to 15
>
> np.random.seed(1)
>
> *# Here's the statement which assigns the initial conditions:*
>
> x0 = -15 + 30 * np.random.random((N_trajectories, 3))
>
> ******************
>
> I tried simply doing this:
>
> x0 = (-1,0,0.5)
>
> but I get this error:
>
> ValueError: need more than 1 value to unpack
>
>
> What am I missing? What is the correct way to make the assignment?
>
>
> Thanks!
>
>
> --Prahas
>
>
>
>
>