matplotlib-users Mailing List for matplotlib

As related to another question(s) I've posted, can someone help with this
custom formatter? This is for use in a FunctionFormatter to be used on the
y axis to format the ticks (in particular, to remove them when not
wanted). Example:
def CustomFormatter(self,y,i):
 if y < 0:
 return ''
This says if the value of y < 0, put nothing on the axis tick.
QUESTION: How can I implement the following two sorts of rules in
Matplotlib's (OO) API?
def CustomFormatter(self,y,i):
 if y falls in the bottom 50 pixels' worth of height of this plot:
 return ''
or
def CustomFormatter(self,y,i):
 if y falls in the bottom 10% of the height of this plot:
 return ''
Thanks,
Che

Hello,
 
I am fairly new to Matplotlib and appreciate your help with my question:
 
I am looking to generate a time series trend plots and include as my
xtick labels a selective list of strings. For ex: Month/Year label for
data corresponding to the 1st day of each month. I may be plotting 365
days of data but want to show only 12 xtick labels. 
 
Would it be possible to specify grid lines for every 7 days of data for
instance? This makes the grid line locations different from the xtick
label locations. 
 
I am sure there is support for such a feature in Matplotlib. I did look
through the docs/forums but could not find much help.
Any suggestions will be much appreciated. 
 
Thanks,
Shankar

> 
> From: "Marianne C." <mar...@gm...>
> Date: November 24, 2011 6:48:34 AM PST
> To: mat...@li...
> Subject: [Matplotlib-users] Removing ticks and frame (imshow)
> 
> 
> Hi all,
> 
> My name is Marianne, I am a beginner user of matplotlib.
> I am using imshow in pyplot. I am desperate to get rid of
> the ticks on both x and y axes (see attached picture). I
> do not need the black box around the data either. Should
> I use imshow in axes.Axes instead, to be able to call
> set_ticks_position("none")?
> Thank you for your help,
> Marianne
> 
> Here is the code so far:
> 
> import numpy
> from matplotlib import pyplot
> 
> q=numpy.loadtxt('field.txt')
> 
> myfield = pyplot.imshow(q,aspect=1)
> myfield.set_clim(vmin=0, vmax=0.6)
> 
> pyplot.colorbar()
> 
> pyplot.savefig('field_1.eps')
> 
> <field_1.pdf>
Marianne,
Try
myfield.get_axes().axis('off')
-Sterling

On Thu, Nov 24, 2011 at 9:48 AM, Marianne C. <mar...@gm...> wrote:
> Hi all,
>
> My name is Marianne, I am a beginner user of matplotlib.
> I am using imshow in pyplot. I am desperate to get rid of
> the ticks on both x and y axes (see attached picture). I
> do not need the black box around the data either. Should
> I use imshow in axes.Axes instead, to be able to call
>
> set_ticks_position("none")?
>
> Thank you for your help,
> Marianne
>
> Here is the code so far:
>
> import numpy
> from matplotlib import pyplot
>
> q=numpy.loadtxt('field.txt')
>
> myfield = pyplot.imshow(q,aspect=1)
> myfield.set_clim(vmin=0, vmax=0.6)
>
> pyplot.colorbar()
>
> pyplot.savefig('field_1.eps')
>
There are a number of ways to accomplish this, but the one I use is to make
the x and y axes invisible (gets rid of the ticks) and also make the spines
invisible (gets rid of the lines). I just throw these changes into a
utility function (`clear_frame` below) and put that in a module that's on
my python path so that it's easily reusable.
Hope that helps,
-Tony
#~~~
import numpy as np
import matplotlib.pyplot as plt
def clear_frame(ax=None):
 if ax is None:
 ax = plt.gca()
 ax.xaxis.set_visible(False)
 ax.yaxis.set_visible(False)
 for spine in ax.spines.itervalues():
 spine.set_visible(False)
img = np.random.random((100,100))
plt.imshow(img)
clear_frame()
plt.colorbar()
plt.show()
#~~~

On 11/22/11 12:51 PM, Dave Xia wrote:
> Hi,
>
> I am a new user of matplotlib Basemap. I tried to draw the latitude 
> with interval 0.1 degree using drawparallels, but failed. I wonder if 
> the drawparallels can draw latitude lines with small interval instead 
> of integer values. (drawmeridian can work with small interval 0.1).
>
> Does anyone have any idea to fix this issue?
>
> Thanks!
>
> Dave
Confirmed. This is now fixed in github master. It's a one-liner, so 
you can manually patch your source if you prefer.
Just change line 2067 in lib/mpl_toolkits/basemap/__init__.py from
if t is not None: linecolls[int(lat)][1].append(t)
to
if t is not None: linecolls[lat][1].append(t)
Regards,
Jeff

On Mon, Nov 28, 2011 at 9:39 PM, Markus Baden <mar...@gm...> wrote:
> anno_args = {
>   'annotation_clip': False,
>   'arrowprops': dict(arrowstyle='-', relpos=(0, 1)),
>   }
> plt.annotate('Good relpos', (3, 3), xytext = (3, 2), **anno_args)
> plt.annotate('Bad relpos', (6, 6), xytext = (6, 5), **anno_args)
This is a bug. In the current implementation, "annotate" has a
side-effect that modifies the arrowprops dictionary.
As a workaround, you may do,
arrowprops = dict(arrowstyle='-', relpos=(0, 1))
plt.annotate('Good relpos', (3, 3), xytext = (3, 2),
 annotation_clip=False, arrowprops=arrowprops.copy())
> plt.annotate('No ha/va', (5, 5), xytext = (5, 4),
> arrowprops=dict(arrowstyle='-'),
>       ha='left', va='top')
>
ha and va controls the location of the text relative to the xytext,
and I believe it does work as expected. It has nothing to do with the
starting point of the arrow, which should be controlled by the relpos
parameter.
Regards,
-JJ

Hi list,
I'm trying to annotate points on a graph by drawing a simple line from the
point on the axis to the top left corner of the text. I can't figure out,
how to use pyplot.annotate so that it turns of the arrow head and I can use
horizontalalignment (ha) and verticalalignment (va). When I use
arrowstyle='-' in the arrowprops dictionary ha and va don't work. Instead I
use relpos=(0, 1) in the arrowprops dictionary, which works, but only when
I call the annotate function the first time. Below is a minimal example.
I'm using mpl version 1.0. as part of EPD 7.1 on Mac OS X 10.5.
Any hints on how to achieve my goal would be greatly appreciated!
Best regards,
Markus
---
The following code reproduces my problem
import numpy as np
import matplotlib.pyplot as plt
data = np.linspace(1,10)
plt.plot(data, data)
anno_args = {
 'annotation_clip': False,
 'arrowprops': dict(arrowstyle='-', relpos=(0, 1)),
 }
plt.annotate('Good relpos', (3, 3), xytext = (3, 2), **anno_args)
plt.annotate('Bad relpos', (6, 6), xytext = (6, 5), **anno_args)
plt.annotate('No ha/va', (5, 5), xytext = (5, 4),
arrowprops=dict(arrowstyle='-'),
 ha='left', va='top')
plt.show()

On 11/27/2011 05:30 PM, Tom Bennett wrote:
> Hi,
> I am new to Matplotlib. I am using matplotlib under ipython. A
> function script generates a figure that has three subplots. The thing is
> that I would like to continue to interact with a specific subplot under
> the interactive prompt through pylab after I run that function. However,
> gca() returns the last subplot which is not what I want.
> The question is if there is any way to tell gca() which Axes is the
> current Axes.
> Thanks,
> Tom
>
If you keep a reference to the Axes when you create it, or if you use 
gca() to return a reference before creating the next one, then you can 
use sca(ax) to make ax the current axes.
Eric
>
>
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Hi,
I am new to Matplotlib. I am using matplotlib under ipython. A
function script generates a figure that has three subplots. The thing is
that I would like to continue to interact with a specific subplot under the
interactive prompt through pylab after I run that function. However, gca()
returns the last subplot which is not what I want.
The question is if there is any way to tell gca() which Axes is the current
Axes.
Thanks,
Tom