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2010年3月27日 Ariel Rokem <ar...@be...>: > I am trying to make a color-map which will respond to the range of values in > the data itself. That is - I want to take one of the mpl colormaps and use > parts of it, depending on the range of the data. > > In particular, I am interested in using the plt.cm.RdYlBu_r colormap. If the > data has both negative and positive values, I want 0 to map to the central > value of this colormap (a pale whitish yellow) and I want negative values to > be in blue and positive numbers to be in red. Also - I would want to use the > parts of the colormap that represent how far away the smallest and largest > values in the data are from 0. So - if my data is in the range [x1,x2] I > would want to use the part of the colormap in indices > 127-127*abs(x1)/(x2-x1) through 127+127*x2/(x2-x1). If the data only > includes positive numbers, I would want to only use the blue part of the > colormap and if there are negative numbers, I would want to only use the red > part of the colormap (in these cases, I would also want to take only a > portion of the colormap which represents the size of the interval [x1,x2] > relative to the interval [0,x1] or [x2,0], as the case may be). > > I think that this might be useful when comparing matrices generated from > different data, but with the same computation, such as correlation or > coherence (see http://nipy.sourceforge.net/nitime/examples/fmri.html to get > an idea of what I mean). I might miss something important, but why not use pcolor() with kwargs vmin and vmax, http://matplotlib.sourceforge.net/api/axes_api.html#matplotlib.axes.Axes.pcolor, e.g.: maxval = numpy.abs(C).max() pcolor(C, vmin = -maxval, vmax = maxval) As far as I can judge, this should have the desired effect. Friedrich
Hi Brian, Thanks for the code - this is definitely in the direction of what I want to make! The RdYlBu_r colormap is one of the built-in colormaps available in matplotlib.pyplot.cm (you can see all of them here: http://www.scipy.org/Cookbook/Matplotlib/Show_colormaps). I think that using the built-in colormaps might give nicer transitions between the colors, so instead of transitioning linearily between red and white and white and blue, it transitions in a slightly non-linear way, along several segments. Compare: plot(plt.cm.RdYlBu_r(arange(256))) with plot(my_cmap(arange(256))) I think that the more nonlinear one might look a little bit nicer (and might be less perceptually misleading in interpreting color differences in the result). But I need to figure out how many segments there are in there. Thanks - Ariel On Sat, Mar 27, 2010 at 4:14 AM, Brian Blais <bb...@br...> wrote: > On Mar 27, 2010, at 1:13 , Ariel Rokem wrote: > > In particular, I am interested in using the plt.cm.RdYlBu_r colormap. If > the data has both negative and positive values, I want 0 to map to the > central value of this colormap (a pale whitish yellow) and I want negative > values to be in blue and positive numbers to be in red. > > > not sure if this is what you want (I'd never heard of RdYlBu_r...I need to > go read up!), but I've used a similar colormap with the code posted below. > You might be able to modify it for your case. > > > hope this helps! > > bb > > from pylab import * > > def bluewhitered(a,N=256): > bottom = [0, 0, 0.5] > botmiddle = [0, 0.5, 1] > middle = [1, 1, 1] > topmiddle = [1, 0, 0] > top = [0.5, 0, 0] > > lims=[a.min(),a.max()] > > if lims[0]<0 and lims[1]>0: > ratio=abs(lims[0])/(abs(lims[0])+lims[1]) > > cdict={} > cdict['red']=[] > cdict['green']=[] > cdict['blue']=[] > > # negative part > red=[(0.0, 0.0, 0.0), > (ratio/2, 0.0, 0.0), > (ratio, 1.0, 1.0)] > green=[(0.0, 0.0, 0.0), > (ratio/2, 0.5, 0.5), > (ratio, 1.0, 1.0)] > blue=[(0.0, 0.5, 0.5), > (ratio/2, 1, 1), > (ratio, 1.0, 1.0)] > > cdict['red'].extend(red) > cdict['green'].extend(green) > cdict['blue'].extend(blue) > > nratio=1-(1-ratio)/2.0 > # positive part > red=[(ratio, 1.0, 1.0), > (nratio, 1.0, 1.0), > (1, 0.5, 0.5)] > green=[(ratio, 1.0, 1.0), > (nratio, 0., 0.), > (1, 0.0, 0.0)] > blue=[(ratio, 1., 1.), > (nratio, 0, 0), > (1, 0, 0)] > > cdict['red'].extend(red) > cdict['green'].extend(green) > cdict['blue'].extend(blue) > > > > > elif lims[0]>=0: # all positive > cdict={} > cdict['red']=[] > cdict['green']=[] > cdict['blue']=[] > > ratio=0.0 > nratio=0.5 > > # positive part > red=[(ratio, 1.0, 1.0), > (nratio, 1.0, 1.0), > (1, 0.5, 0.5)] > green=[(ratio, 1.0, 1.0), > (nratio, 0., 0.), > (1, 0.0, 0.0)] > blue=[(ratio, 1., 1.), > (nratio, 0, 0), > (1, 0, 0)] > > cdict['red'].extend(red) > cdict['green'].extend(green) > cdict['blue'].extend(blue) > > else: # all negative > cdict={} > cdict['red']=[] > cdict['green']=[] > cdict['blue']=[] > > ratio=1.0 > > # negative part > red=[(0.0, 0.0, 0.0), > (ratio/2, 0.0, 0.0), > (ratio, 1.0, 1.0)] > green=[(0.0, 0.0, 0.0), > (ratio/2, 0.5, 0.5), > (ratio, 1.0, 1.0)] > blue=[(0.0, 0.5, 0.5), > (ratio/2, 1, 1), > (ratio, 1.0, 1.0)] > > cdict['red'].extend(red) > cdict['green'].extend(green) > cdict['blue'].extend(blue) > > my_cmap = > matplotlib.colors.LinearSegmentedColormap('my_colormap',cdict,N) > > > return my_cmap > > if __name__=="__main__": > > a=randn(20,20) > my_cmap=bluewhitered(a,256) > > > > clf() > pcolor(a,cmap=my_cmap) > colorbar() > > > > > > > > -- > Brian Blais > bb...@br... > http://web.bryant.edu/~bblais <http://web.bryant.edu/%7Ebblais> > http://bblais.blogspot.com/ > > > > -- Ariel Rokem Helen Wills Neuroscience Institute University of California, Berkeley http://argentum.ucbso.berkeley.edu/ariel
Hi, thanks for the suggestion. They do have multiple versions but I checked that everything is using 2.5 regards, Ken Dere Rune V. Sjøen wrote: > Hi, > > Does the box have multiple python versions installed, and are you sure > that apache is using the > same version and/or site packages as when you run it from the command line > ? > > Regards, > Rune V. Sjøen > > On Fri, Mar 26, 2010 at 8:07 PM, Ken Dere > <kp...@ve...> wrote: > >> Hi, >> >> I am trying to import pylab into an application running under an Apache >> wsgi >> server. The error I get is that if it tries to import matplotlib.cbook. >> The application can import numpy, scipy etc just fine. >> >> the error message is that matplotlib has no module cbook. >> >> I can import matplotlib OK but if a do a dir(matplolib) it does indeed >> not include cbook. >> >> If I try to import pylab from the command line it works fine and >> pylab.cbook >> is found. >> >> Any suggestions would be appreciated. >> >> >> K. Dere >> >> >> >> ------------------------------------------------------------------------------ >> Download Intel® Parallel Studio Eval >> Try the new software tools for yourself. Speed compiling, find bugs >> proactively, and fine-tune applications for parallel performance. >> See why Intel Parallel Studio got high marks during beta. >> http://p.sf.net/sfu/intel-sw-dev >> _______________________________________________ >> Matplotlib-users mailing list >> Mat...@li... >> https://lists.sourceforge.net/lists/listinfo/matplotlib-users >> -- K. Dere
On Mar 27, 2010, at 1:13 , Ariel Rokem wrote: > In particular, I am interested in using the plt.cm.RdYlBu_r > colormap. If the data has both negative and positive values, I want > 0 to map to the central value of this colormap (a pale whitish > yellow) and I want negative values to be in blue and positive > numbers to be in red. not sure if this is what you want (I'd never heard of RdYlBu_r...I need to go read up!), but I've used a similar colormap with the code posted below. You might be able to modify it for your case. hope this helps! bb from pylab import * def bluewhitered(a,N=256): bottom = [0, 0, 0.5] botmiddle = [0, 0.5, 1] middle = [1, 1, 1] topmiddle = [1, 0, 0] top = [0.5, 0, 0] lims=[a.min(),a.max()] if lims[0]<0 and lims[1]>0: ratio=abs(lims[0])/(abs(lims[0])+lims[1]) cdict={} cdict['red']=[] cdict['green']=[] cdict['blue']=[] # negative part red=[(0.0, 0.0, 0.0), (ratio/2, 0.0, 0.0), (ratio, 1.0, 1.0)] green=[(0.0, 0.0, 0.0), (ratio/2, 0.5, 0.5), (ratio, 1.0, 1.0)] blue=[(0.0, 0.5, 0.5), (ratio/2, 1, 1), (ratio, 1.0, 1.0)] cdict['red'].extend(red) cdict['green'].extend(green) cdict['blue'].extend(blue) nratio=1-(1-ratio)/2.0 # positive part red=[(ratio, 1.0, 1.0), (nratio, 1.0, 1.0), (1, 0.5, 0.5)] green=[(ratio, 1.0, 1.0), (nratio, 0., 0.), (1, 0.0, 0.0)] blue=[(ratio, 1., 1.), (nratio, 0, 0), (1, 0, 0)] cdict['red'].extend(red) cdict['green'].extend(green) cdict['blue'].extend(blue) elif lims[0]>=0: # all positive cdict={} cdict['red']=[] cdict['green']=[] cdict['blue']=[] ratio=0.0 nratio=0.5 # positive part red=[(ratio, 1.0, 1.0), (nratio, 1.0, 1.0), (1, 0.5, 0.5)] green=[(ratio, 1.0, 1.0), (nratio, 0., 0.), (1, 0.0, 0.0)] blue=[(ratio, 1., 1.), (nratio, 0, 0), (1, 0, 0)] cdict['red'].extend(red) cdict['green'].extend(green) cdict['blue'].extend(blue) else: # all negative cdict={} cdict['red']=[] cdict['green']=[] cdict['blue']=[] ratio=1.0 # negative part red=[(0.0, 0.0, 0.0), (ratio/2, 0.0, 0.0), (ratio, 1.0, 1.0)] green=[(0.0, 0.0, 0.0), (ratio/2, 0.5, 0.5), (ratio, 1.0, 1.0)] blue=[(0.0, 0.5, 0.5), (ratio/2, 1, 1), (ratio, 1.0, 1.0)] cdict['red'].extend(red) cdict['green'].extend(green) cdict['blue'].extend(blue) my_cmap = matplotlib.colors.LinearSegmentedColormap ('my_colormap',cdict,N) return my_cmap if __name__=="__main__": a=randn(20,20) my_cmap=bluewhitered(a,256) clf() pcolor(a,cmap=my_cmap) colorbar() -- Brian Blais bb...@br... http://web.bryant.edu/~bblais http://bblais.blogspot.com/
Hi everyone, I am trying to make a color-map which will respond to the range of values in the data itself. That is - I want to take one of the mpl colormaps and use parts of it, depending on the range of the data. In particular, I am interested in using the plt.cm.RdYlBu_r colormap. If the data has both negative and positive values, I want 0 to map to the central value of this colormap (a pale whitish yellow) and I want negative values to be in blue and positive numbers to be in red. Also - I would want to use the parts of the colormap that represent how far away the smallest and largest values in the data are from 0. So - if my data is in the range [x1,x2] I would want to use the part of the colormap in indices 127-127*abs(x1)/(x2-x1) through 127+127*x2/(x2-x1). If the data only includes positive numbers, I would want to only use the blue part of the colormap and if there are negative numbers, I would want to only use the red part of the colormap (in these cases, I would also want to take only a portion of the colormap which represents the size of the interval [x1,x2] relative to the interval [0,x1] or [x2,0], as the case may be). I think that this might be useful when comparing matrices generated from different data, but with the same computation, such as correlation or coherence (see http://nipy.sourceforge.net/nitime/examples/fmri.html to get an idea of what I mean). First of all - is this a good idea? Or in other words - is there any reason I am not thinking of why this idea is a really bad idea? Second - the technical questions. I think that I can make this happen by using matplotlib.colors.LinearSegmentedColormap, after fiddling with the values of the color-map a bit (as described above), but in order to do that, I need to know what segmentdata was used in order to generate the original colormap (for example, how many lines did each of the entries in the cdict have? Looking at a plot of the cmap it looks like there must have been 8 or 9 for RdYlBu_r, but I can't be sure). I could analyze it in more detail to get that out empirically, but I am guessing that someone around here might be able to spare me that lunacy (if not others...). Thanks in advance, Ariel -- Ariel Rokem Helen Wills Neuroscience Institute University of California, Berkeley http://argentum.ucbso.berkeley.edu/ariel
Greetings everyone, This year, there will be two days of tutorials (June 28th and 29th) before the main SciPy 2010 conference. Each of the two tutorial tracks (intro, advanced) will have a 3-4 hour morning and afternoon session both days, for a total of 4 intro sessions and 4 advanced sessions. The main tutorial web page for SciPy 2010 is here: http://conference.scipy.org/scipy2010/tutorials.html We are currently in the process of planning the tutorial sessions. You can help us in two ways: Brainstorm/vote on potential tutorial topics ============================================ To help us plan the tutorials, we have setup a web site that allow everyone in the community to brainstorm and vote on tutorial ideas/topics. The website for brainstorming/voting is here: http://conference.scipy.org/scipy2010/tutorialsUV.html The tutorial committee will use this information to help select the tutorials. Please jump in and let us know what tutorial topics you would like to see. Tutorial proposal submissions ============================= We are now accepting tutorial proposals from individuals or teams that would like to present a tutorial. Tutorials should be focused on covering a well defined topic in a hands on manner. We want to see tutorial attendees coding! We are pleased to offer tutorial presenters stipends this year for the first time: * 1 Session: 1,000ドル (half day) * 2 Sessions: 1,500ドル (full day) Optionally, part of this stipend can be applied to the presenter's registration costs. To submit a tutorial proposal please submit the following materials to 201...@sc... by April 15: * A short bio of the presenter or team members. * Which track the tutorial would be in (intro or advanced). * A short description and/or outline of the tutorial content. * A list of Python packages that attendees will need to have installed to follow along.
2010年3月26日 timothee cezard <tc...@st...>: > does it make sense to use something like > plt.bar(bins, nb_per_bin, width=(max(bins)-min(bins)) / (1.5*len(bins))) I think that should work, although you should use (max(bins) - min(bins) / 1.5 / (len(bins) - 1), but I would suggest: bounds = {some N + 1 array} center = 0.5 * (bounds[1:] + bounds[:-1]) width = 0.9 * (bounds[1:] - bounds[:-1]) offset = 0.5 * width plt.bar(center - offset, {some N array}, width = width) but I haven't tested it. bar() does accept an iterable as *width* argument. Friedrich