matplotlib-users Mailing List for matplotlib

_cntr.so has been deprecated (it might take a couple of releases before we
remove it entirely). _contour.so has a newer, better interface and comes
with a python wrapper. Don't know if that is an issue at all for you, just
noting that is the case.
I might also suggest looking at scikit-image, as I think it has some
contouring algorithms that might be easier to link to.
Ben Root
On Thu, Jun 25, 2015 at 2:28 PM, Sterling Smith <sm...@fu...>
wrote:
> The contour finder in matplotlib is more robust than I currently have in a
> legacy fortran project. I would like to link to matplotlib’s instead. Has
> anyone done this before? Are there any suggestions or pitfalls for
> proceeding?
>
> Thanks,
> Sterling
>
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The contour finder in matplotlib is more robust than I currently have in a legacy fortran project. I would like to link to matplotlib’s instead. Has anyone done this before? Are there any suggestions or pitfalls for proceeding?
Thanks,
Sterling

The mplot3d tutorial page, which is the first result when you google
'mplot3d', includes a section on 'Tri-surface plots' and is precisely what
you are looking for.
You certainly do not need to use scipy. Matplotlib includes its own
Delaunay triangulator, as specified in the 'triangular grids'
documentation, which is the first result when you google 'matplotlib
triangulation'.
Ian
On 25 June 2015 at 12:22, Philipp A. <fly...@we...> wrote:
> hi!
>
> do a delaunay triangulation
> <http://docs.scipy.org/doc/scipy-0.14.0/reference/generated/scipy.spatial.Delaunay.html>
> on them.
>
> also try to do the triangulation only on the xy coordinates and see which
> of both gives the results you like more.
>
> best, p
>
> justonium <jus...@gm...> schrieb am Do., 25. Juni 2015 um
> 05:21 Uhr:
>
>> I have a set of three dimensional coordinates, each of which is on a
>> landscape. I would like to visualize the entire landscape.
>>
>> I've already tried plotting the points in 3D space using Axes3D.scatter,
>> but
>> I just see a bunch of points, and it's hard to visually understand what's
>> going on.
>>
>> Ideally, I would like to view a wireframe plot. In order for this to be
>> drawn, height values will need to be interpolated from the samples that I
>> have, which don't line up with a grid.
>>
>> Another solution might be:
>>
>> For each point, draw a vertical line from it, straight down, to a point
>> below it which has the same x and y coordinates, with 0 as the z
>> coordinate.
>> This might still be difficult to visually understand.
>>
>>
>>
>> --
>> View this message in context:
>> http://matplotlib.1069221.n5.nabble.com/How-can-I-visualize-a-landscape-which-I-have-sample-heights-of-tp45834.html
>> Sent from the matplotlib - users mailing list archive at Nabble.com.
>>
>>
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>> network devices and physical & virtual servers, alerts via email & sms
>> for fault. Monitor 25 devices for free with no restriction. Download now
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>
>
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> for fault. Monitor 25 devices for free with no restriction. Download now
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>

Is there any way to do this? The example here works in Cartesian
coordinates:
http://matplotlib.org/examples/pylab_examples/coords_report.html
but if you change
subplots()
to
subplots(subplot_kw={'polar':True})
Then the millions() function is never even called.
Thanks,
Alex

hi!
do a delaunay triangulation
<http://docs.scipy.org/doc/scipy-0.14.0/reference/generated/scipy.spatial.Delaunay.html>
on them.
also try to do the triangulation only on the xy coordinates and see which
of both gives the results you like more.
best, p
justonium <jus...@gm...> schrieb am Do., 25. Juni 2015 um
05:21 Uhr:
> I have a set of three dimensional coordinates, each of which is on a
> landscape. I would like to visualize the entire landscape.
>
> I've already tried plotting the points in 3D space using Axes3D.scatter,
> but
> I just see a bunch of points, and it's hard to visually understand what's
> going on.
>
> Ideally, I would like to view a wireframe plot. In order for this to be
> drawn, height values will need to be interpolated from the samples that I
> have, which don't line up with a grid.
>
> Another solution might be:
>
> For each point, draw a vertical line from it, straight down, to a point
> below it which has the same x and y coordinates, with 0 as the z
> coordinate.
> This might still be difficult to visually understand.
>
>
>
> --
> View this message in context:
> http://matplotlib.1069221.n5.nabble.com/How-can-I-visualize-a-landscape-which-I-have-sample-heights-of-tp45834.html
> Sent from the matplotlib - users mailing list archive at Nabble.com.
>
>
> ------------------------------------------------------------------------------
> Monitor 25 network devices or servers for free with OpManager!
> OpManager is web-based network management software that monitors
> network devices and physical & virtual servers, alerts via email & sms
> for fault. Monitor 25 devices for free with no restriction. Download now
> http://ad.doubleclick.net/ddm/clk/292181274;119417398;o
> _______________________________________________
> Matplotlib-users mailing list
> Mat...@li...
> https://lists.sourceforge.net/lists/listinfo/matplotlib-users
>

I have a set of three dimensional coordinates, each of which is on a
landscape. I would like to visualize the entire landscape.
I've already tried plotting the points in 3D space using Axes3D.scatter, but
I just see a bunch of points, and it's hard to visually understand what's
going on.
Ideally, I would like to view a wireframe plot. In order for this to be
drawn, height values will need to be interpolated from the samples that I
have, which don't line up with a grid.
Another solution might be:
For each point, draw a vertical line from it, straight down, to a point
below it which has the same x and y coordinates, with 0 as the z coordinate.
This might still be difficult to visually understand.
--
View this message in context: http://matplotlib.1069221.n5.nabble.com/How-can-I-visualize-a-landscape-which-I-have-sample-heights-of-tp45834.html
Sent from the matplotlib - users mailing list archive at Nabble.com.