matplotlib-users Mailing List for matplotlib

On Tue, Jan 22, 2013 at 1:57 PM, David Erickson <hal...@gm...>wrote:
> Hello-
> Prior to version 1.2 of MPL I was able to hide labels for certain
> lines in the legend by setting the label=None when plotting a line,
> however in 1.2 it is now showing the legend entry and visibly printing
> "None". Is there a workaround to hide the label?
>
> Thanks,
> David
>
>
I think you want "_nolegend_" for those labels. The hiding of the labels
for None was an undocumented feature, I think, and has been "fixed".
http://matplotlib.org/api/axes_api.html#matplotlib.axes.Axes.legend
Cheers!
Ben Root

Hi Paul,
This doesn't solve my problem since the whole point was to have two
separate x axes with different scales, etc. One thing that I found that
does help is to use the suptitle() method of figure. This at least puts
the title at the top of the figure and I can then fiddle with the top
offset for the subplot to get the title to not overlap the axis label.
Jon
On Tue, 2013年01月22日 at 13:02 -0800, Paul Hobson wrote:
> 
> On Tue, Jan 22, 2013 at 12:22 PM, Jonathan Slavin
> <js...@cf...> wrote:
> Hi,
> 
> I'm having some trouble with using twiny and a title on the
> plot. The
> title is writing over the axis label -- and even the tick
> labels. I've
> tried tight_layout() but it doesn't seem to help. I could use
> fig.text
> instead of title and place the title text where I want it
> (with a bit of
> fiddling), but it'd be nice to have a more elegant solution.
> 
> 
> Try this is a workaround:
> fig, ax1 = plt.subplots()
> ax2 = ax1.twiny()
> ax1.plot(np.random.randn(50), 'gs')
> ax2.plot(np.random.randn(50), 'bo')
> ax1.set_title('Test Title')
> ax2.xaxis.tick_bottom()
> plt.show()
> 
> Does that help?
> -paul
> 
> 
-- 
______________________________________________________________
Jonathan D. Slavin Harvard-Smithsonian CfA
js...@cf... 60 Garden Street, MS 83
phone: (617) 496-7981 Cambridge, MA 02138-1516
 cell: (781) 363-0035 USA
______________________________________________________________

On Tue, Jan 22, 2013 at 12:22 PM, Jonathan Slavin
<js...@cf...>wrote:
> Hi,
>
> I'm having some trouble with using twiny and a title on the plot. The
> title is writing over the axis label -- and even the tick labels. I've
> tried tight_layout() but it doesn't seem to help. I could use fig.text
> instead of title and place the title text where I want it (with a bit of
> fiddling), but it'd be nice to have a more elegant solution.
>
Try this is a workaround:
fig, ax1 = plt.subplots()
ax2 = ax1.twiny()
ax1.plot(np.random.randn(50), 'gs')
ax2.plot(np.random.randn(50), 'bo')
ax1.set_title('Test Title')
ax2.xaxis.tick_bottom()
plt.show()
Does that help?
-paul

Hi,
I'm having some trouble with using twiny and a title on the plot. The
title is writing over the axis label -- and even the tick labels. I've
tried tight_layout() but it doesn't seem to help. I could use fig.text
instead of title and place the title text where I want it (with a bit of
fiddling), but it'd be nice to have a more elegant solution.
Jon
-- 
______________________________________________________________
Jonathan D. Slavin Harvard-Smithsonian CfA
js...@cf... 60 Garden Street, MS 83
phone: (617) 496-7981 Cambridge, MA 02138-1516
 cell: (781) 363-0035 USA
______________________________________________________________

Hello-
Prior to version 1.2 of MPL I was able to hide labels for certain
lines in the legend by setting the label=None when plotting a line,
however in 1.2 it is now showing the legend entry and visibly printing
"None". Is there a workaround to hide the label?
Thanks,
David

On Mon, Jan 21, 2013 at 8:06 PM, Pau <vim...@go...> wrote:
> Hi,
>
> I am somehow new to matplotlib and I am trying to plot this function of x
> ,y ,z
>
> F(x,y,z)=
> 38244.74787*Pi*(x^2+y^2+z^2)^.125+1615.975261*Pi*z^2/(x^2+y^2+z^2)^.875-1292.780210*Pi*z^2/((x^2+y^2+z^2)^.875*(1+y^2/x^2))+1292.78*Pi*(x^2+y^2+z^2)^.125/(1+y^2/x^2)
>
> in a similar way as
>
> http://matplotlib.org/mpl_examples/mplot3d/contour3d_demo3.hires.png
>
> The code is
> http://matplotlib.org/mpl_examples/mplot3d/contour3d_demo3.py
>
> But I have no idea where to start...
>
> some help would be appreciated...
>
> thanks
>
>
The reason you are having difficulty coming up with a way to plot this is
because you have 3 input dimensions, and 1 output dimension that you wish
to plot. If you were to plot this in 3D space, it would have to be done as
F(x,y,z) as a colored "mist" in the domain of (x,y,z). While a "mist"
can't be done in mplot3d, you could plot out scatter points to emulate
this. One could also use contourf3d(..., zdir='z', offset=...) to create
slices of the filled contours, similar to this example:
http://matplotlib.org/examples/mplot3d/contourf3d_demo2.html
Now, if the domain of (x,y,z) can be parameterized as a surface (i.e., a
sphere or a cylinder), then you are looking to do an image of F(x,y,z)
plotted on that surface, which is a little bit difficult, but also do-able
using the plot_surface() function.
Cheers!
Ben Root

Hello everyone,
in my program I'm encountering an error when calling the function axes.set_xticks (Matplotlib 1.2.0 on python 2.7-64 bit). It is really difficult for me to build a test case, because my program is really complex. Here is the error traceback:
File "C:\Python27\Lib\site-packages\matplotlib\axes.py", line 2596, in set_xticks
 return self.xaxis.set_ticks(ticks, minor=minor)
File "C:\Python27\Lib\site-packages\matplotlib\axis.py", line 1489, in set_ticks
 self.set_view_interval(min(ticks), max(ticks))
File "C:\Python27\Lib\site-packages\matplotlib\axis.py", line 1771, in set_view_interval
 max(vmin, vmax, Vmax))
File "C:\Python27\Lib\site-packages\matplotlib\transforms.py", line 932, in _set_intervalx
 self.invalidate()
File "C:\Python27\Lib\site-packages\matplotlib\transforms.py", line 131, in invalidate
 return self._invalidate_internal(value, invalidating_node=self)
File "C:\Python27\Lib\site-packages\matplotlib\transforms.py", line 155, in _invalidate_internal
 invalidating_node=self)
File "C:\Python27\Lib\site-packages\matplotlib\transforms.py", line 155, in _invalidate_internal
 invalidating_node=self)
File "C:\Python27\Lib\site-packages\matplotlib\transforms.py", line 155, in _invalidate_internal
 invalidating_node=self)
File "C:\Python27\Lib\site-packages\matplotlib\transforms.py", line 2141, in _invalidate_internal
 invalidating_node=invalidating_node)
File "C:\Python27\Lib\site-packages\matplotlib\transforms.py", line 155, in _invalidate_internal
 invalidating_node=self)
File "C:\Python27\Lib\site-packages\matplotlib\transforms.py", line 2141, in _invalidate_internal
 invalidating_node=invalidating_node)
File "C:\Python27\Lib\site-packages\matplotlib\transforms.py", line 153, in _invalidate_internal
 for parent in self._parents.itervalues():
File "C:\Python27\Lib\weakref.py", line 147, in itervalues
 for wr in self.data.itervalues(): 
RuntimeError: dictionary changed size during iteration
I googled and found that this is a well known bug due to the use of self.data.itervalues() in the for loop (i think the correct syntax should be for wr in iter(self.data.items()). So I would like to point out the bug (if it is) to the matplotlib guys, how can I do it?
In the meantime, how can I work around it without changing the source code?
Thanks in advance!
 		 	 		 

On Mon, Jan 21, 2013 at 10:12 PM, <jos...@gm...> wrote:
> On Mon, Jan 21, 2013 at 5:01 AM, cnorn <ch...@gm...> wrote:
>> Are there any way to make column scatter plots with matplotlib. They are also
>> called beeswarm plot. plotSpread is implemented in matlab, which seems to do
>> the job, but I can't find it in matplotlib.
>
>
> somewhat similar, with random jitter and violins
>
> http://statsmodels.sourceforge.net/devel/generated/statsmodels.graphics.boxplots.beanplot.html
> https://picasaweb.google.com/lh/photo/SF2eFYvMcgEknynXlSYEG9MTjNZETYmyPJy0liipFm0?feat=directlink
turning off some colors (full set of options are available):
https://picasaweb.google.com/lh/photo/41edXo0ZeO6qUreNeUvJmdMTjNZETYmyPJy0liipFm0?feat=directlink
>
> plotSpread looks like it might have a fancier point selection
If someone can come up with more regular "bees" like here
http://stackoverflow.com/questions/9777592/beeswarm-boxplot-scatterplot-for-categorical-data-in-matlab
then it would make a nice enhancement.
Josef
>
> Josef
>
>>
>> Thanks,
>> Chris
>>
>>
>>
>>
>> --
>> View this message in context: http://matplotlib.1069221.n5.nabble.com/How-to-make-column-scatter-plots-tp40276.html
>> Sent from the matplotlib - users mailing list archive at Nabble.com.
>>
>> ------------------------------------------------------------------------------
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On Mon, Jan 21, 2013 at 5:01 AM, cnorn <ch...@gm...> wrote:
> Are there any way to make column scatter plots with matplotlib. They are also
> called beeswarm plot. plotSpread is implemented in matlab, which seems to do
> the job, but I can't find it in matplotlib.
somewhat similar, with random jitter and violins
http://statsmodels.sourceforge.net/devel/generated/statsmodels.graphics.boxplots.beanplot.html
https://picasaweb.google.com/lh/photo/SF2eFYvMcgEknynXlSYEG9MTjNZETYmyPJy0liipFm0?feat=directlink
plotSpread looks like it might have a fancier point selection
Josef
>
> Thanks,
> Chris
>
>
>
>
> --
> View this message in context: http://matplotlib.1069221.n5.nabble.com/How-to-make-column-scatter-plots-tp40276.html
> Sent from the matplotlib - users mailing list archive at Nabble.com.
>
> ------------------------------------------------------------------------------
> Master Visual Studio, SharePoint, SQL, ASP.NET, C# 2012, HTML5, CSS,
> MVC, Windows 8 Apps, JavaScript and much more. Keep your skills current
> with LearnDevNow - 3,200 step-by-step video tutorials by Microsoft
> MVPs and experts. SALE 99ドル.99 this month only -- learn more at:
> http://p.sf.net/sfu/learnmore_122412
> _______________________________________________
> Matplotlib-users mailing list
> Mat...@li...
> https://lists.sourceforge.net/lists/listinfo/matplotlib-users

Hi,
I am somehow new to matplotlib and I am trying to plot this function of x ,y ,z
F(x,y,z)= 38244.74787*Pi*(x^2+y^2+z^2)^.125+1615.975261*Pi*z^2/(x^2+y^2+z^2)^.875-1292.780210*Pi*z^2/((x^2+y^2+z^2)^.875*(1+y^2/x^2))+1292.78*Pi*(x^2+y^2+z^2)^.125/(1+y^2/x^2)
in a similar way as
http://matplotlib.org/mpl_examples/mplot3d/contour3d_demo3.hires.png
The code is
http://matplotlib.org/mpl_examples/mplot3d/contour3d_demo3.py
But I have no idea where to start...
some help would be appreciated...
thanks