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When I plot contours in a stereographic south pole plot with a bounding 
latitude and the rounded clipping
Basemap(projection='spaeqd',lat_0=-90,lon_0=180,resolution='l',boundinglat=-40,round=True)
I see that the contours are correctly cut-off but not the contour 
labels. They appear to be plotted according to a rectangular frame and 
not the rounded one (see attached figure).
Is it possible to mask the labels without having to mask the data?
This issue may be related to an older topic:
http://www.mail-archive.com/mat...@li.../msg02892.html
and to a more recent bugfix
https://github.com/matplotlib/basemap/pull/89
but I do not see any other clue
thanks in advance
marcello
-- 
Dr Marcello Vichi
Centro Euro-Mediterraneo sui Cambiamenti Climatici (CMCC)
Istituto Nazionale di Geofisica e Vulcanologia (INGV)
Viale Aldo Moro 44, 40127 Bologna. Italy
Tel: +39 051 3782631 Fax: +39 051 3782654
Email: mar...@cm..., mar...@bo...
skype: marcello_vichi

Thanks a lot! Works now!
--
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On 02/19/2013 01:52 PM, patricia wrote:
> Thanks Andreas,
> Yes I usually do the same, but in this case I am not managing to do it due
> to the functions being used. It does not allow me to put (7,3, nfig) inside
> the "xx = TaylorDiagram(refstd, fig=fig, rect=122, label="xx")".
> This is the code that I am using:
> http://old.nabble.com/Taylor-diagram-(2nd-take)-p33364690.html
> Do you see an easy way of adding more than 9 Taylor diagrams subplots in
> test1 for example?
>From how I understand the FA.FloatingSubplot docstring (I'm running
1.1.1rc), you could try
 class TaylorDiagram(object):
 def __init__(self, refstd, fig=None, rect=(1, 1, 1), label='_',
srange=(0,1.5)):
 ...
 from matplotlib.projections import PolarAxes
 import mpl_toolkits.axisartist.floating_axes as FA
 import mpl_toolkits.axisartist.grid_finder as GF
 ...
 ax = FA.FloatingSubplot(fig, rect[0], rect[1], rect[2],
grid_helper=ghelper)
 fig.add_subplot(ax)
 ...
 dia = TaylorDiagram(refstd, fig=fig, rect=(3, 7, nrfig, label="EM")
FA.FloatingSubplot docstring says:
 Definition:FA.FloatingSubplot(self, fig, *args, **kwargs)
 Docstring:
 *fig* is a :class:`matplotlib.figure.Figure` instance.
 *args* is the tuple (*numRows*, *numCols*, *plotNum*), where
 the array of subplots in the figure has dimensions *numRows*,
 *numCols*, and where *plotNum* is the number of the subplot
 being created. *plotNum* starts at 1 in the upper left
 corner and increases to the right.
 If *numRows* <= *numCols* <= *plotNum* < 10, *args* can be the
 decimal integer *numRows* * 100 + *numCols* * 10 + *plotNum*.
Hope that helps,
A.

Thanks Andreas,
Yes I usually do the same, but in this case I am not managing to do it due
to the functions being used. It does not allow me to put (7,3, nfig) inside
the "xx = TaylorDiagram(refstd, fig=fig, rect=122, label="xx")".
This is the code that I am using:
http://old.nabble.com/Taylor-diagram-(2nd-take)-p33364690.html
Do you see an easy way of adding more than 9 Taylor diagrams subplots in
test1 for example?
Thanks again,
Patricia
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> The " subplot(111) " works only until 9 subplots, and this function does
> not allow me to put rect=(7,3,nrfig). I get the error: 
> 'Single argument to subplot must be a 3-digit integer')
> ValueError: Single argument to subplot must be a 3-digit integer
I always do
 ax = fig.add_subplot(7, 3, nfig)
which works. (in list iterations, make sure nfig starts at 1).
Andreas.

Hi,I want to make a figure with 21 subplots (7 x 3) but I cannot plot more than 9 in the function I am using. 
class TaylorDiagram(object): def __init__(self, refstd, fig=None, rect=111, label='_', srange=(0,1.5)): ... from matplotlib.projections import PolarAxes 
 import mpl_toolkits.axisartist.floating_axes as FA 
 import mpl_toolkits.axisartist.grid_finder as GF ...
 ax = FA.FloatingSubplot(fig, rect, grid_helper=ghelper)
 fig.add_subplot(ax) ... dia = TaylorDiagram(refstd, fig=fig, rect=111, label="EM")
The " subplot(111) " works only until 9 subplots, and this function does not allow me to put rect=(7,3,nrfig). I get the error: 'Single argument to subplot must be a 3-digit integer')ValueError: Single argument to subplot must be a 3-digit integer
Can you please help me? 
Thanks,Patricia 		 	 		 

I found out a \! (negative thin space in Latex) works.
xlabel('$m^3\!/d$')
On Tue, Feb 19, 2013 at 10:15 AM, Mark Bakker <ma...@gm...> wrote:
> Hello List,
>
> I want to put the following text on a graph, for example along the x-axis:
>
> xlabel('$m^3/d$')
>
> This should show the letter m raised to the power 3 and then a slash and
> the letter d.
> When I do this, there appears a large space after the power 3 and the
> slash.
> So much so that the copy editor of the journal I am publishing in asked me
> to remove the extra white space.
>
> Any suggestions on how to do that?
>
> Thanks,
>
> Mark
>

Hello List,
I want to put the following text on a graph, for example along the x-axis:
xlabel('$m^3/d$')
This should show the letter m raised to the power 3 and then a slash and
the letter d.
When I do this, there appears a large space after the power 3 and the slash.
So much so that the copy editor of the journal I am publishing in asked me
to remove the extra white space.
Any suggestions on how to do that?
Thanks,
Mark