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I noticed in your output that another figure seems to have been created (you see its output as "<matplotlib.figure.Figure at 0x1354cb70>"). It would be useful to add some print statements to figure out exactly which line is emitting that. Second, you are calling "plt.savefig()" in the for-loop for the same filename. I suspect that isn't what you want. I am going to assume that you want to save a final figure after the for-loop is complete, right? Also, it would be more clear to use "fig.savefig()" instead of the more "magical" plt.savefig() as the latter would automatically create a figure if one didn't exist for some reason. Ben Root On Sat, May 16, 2015 at 11:57 AM, Thomas Caswell <tca...@gm...> wrote: > This is coming out of the pandas plotting tools, you might get better > answers on their mailing list. > > Tom > > On Sat, May 16, 2015 at 11:51 AM Juan Wu <wuj...@gm...> wrote: > >> Hi, List experts, >> >> I have a matplotlib problem when I tried to use a tool called HDDM. As >> HDDM is another issue, I here just post my problem with Matplotlib. In >> short, the error alarm appeard when I input fig = plt.figure(). I am a >> beginner with those stuff. >> >> I would appreciate if anyone can give me any good pointers. >> >> Thanks so much, >> Juan >> >> ================== >> >> In [8]: fig = plt.figure() >> <matplotlib.figure.Figure at 0x13293890> >> >> In [9]: ax = fig.add_subplot(111, xlabel='RT', ylabel='count', >> title='RT distributions') >> >> In [10]: for i, subj_data in data.groupby('subj_idx'): >> ...: subj_data.rt.hist(bins=20, histtype='step', ax=ax) >> ...: plt.savefig('hddm_demo_fig_00.pdf') >> >> <matplotlib.figure.Figure at 0x1354cb70> >> Traceback (most recent call last): >> >> File "<ipython-input-15-3b0b3c83094c>", line 2, in <module> >> subj_data.rt.hist(bins=20, histtype='step', ax=ax) >> >> File "C:\Anaconda\lib\site-packages\pandas\tools\plotting.py", line >> 2830, in hist_series >> raise AssertionError('passed axis not bound to passed figure') >> >> AssertionError: passed axis not bound to passed figure >> >> (relevant link: >> https://groups.google.com/forum/#!topic/hddm-users/yBeIRJaHGwo >> there very few experts view and reply questions) >> >> >> ------------------------------------------------------------------------------ >> One dashboard for servers and applications across Physical-Virtual-Cloud >> Widest out-of-the-box monitoring support with 50+ applications >> Performance metrics, stats and reports that give you Actionable Insights >> Deep dive visibility with transaction tracing using APM Insight. >> http://ad.doubleclick.net/ddm/clk/290420510;117567292;y >> _______________________________________________ >> Matplotlib-users mailing list >> Mat...@li... >> https://lists.sourceforge.net/lists/listinfo/matplotlib-users >> > > > ------------------------------------------------------------------------------ > One dashboard for servers and applications across Physical-Virtual-Cloud > Widest out-of-the-box monitoring support with 50+ applications > Performance metrics, stats and reports that give you Actionable Insights > Deep dive visibility with transaction tracing using APM Insight. > http://ad.doubleclick.net/ddm/clk/290420510;117567292;y > _______________________________________________ > Matplotlib-users mailing list > Mat...@li... > https://lists.sourceforge.net/lists/listinfo/matplotlib-users > >
Amy, I expect so (but do not have a system to test on). Continuum builds everything on a very old CentOS system and we run our CI tests on ubuntu 12.04 which is of a similar vintage. The crucial packages are `pkg-config`, `freetype-dev` and `libpng-dev` + what ever gui framework you want. Tom On Mon, May 18, 2015 at 10:24 AM Fort, Amy (Subcontractor) < Amy...@te...> wrote: > *Dear matplotlib-users,* > > > > *I have a general question on matplotlib. I see that matplotlib 1.4.3 > supports Python 2.7 (our organization has 2.7.8). We would like to use > matplotlib as a plot tool. Is matplotlib 1.4.3 compatible to run on a > Linux system with RedHat 5.10?* > > > > *Thank you.* > > > > *Amy Fort* > > > > > > > > > > ------------------------------------------------------------------------------ > One dashboard for servers and applications across Physical-Virtual-Cloud > Widest out-of-the-box monitoring support with 50+ applications > Performance metrics, stats and reports that give you Actionable Insights > Deep dive visibility with transaction tracing using APM Insight. > http://ad.doubleclick.net/ddm/clk/290420510;117567292;y > _______________________________________________ > Matplotlib-users mailing list > Mat...@li... > https://lists.sourceforge.net/lists/listinfo/matplotlib-users >
Dear matplotlib-users, I have a general question on matplotlib. I see that matplotlib 1.4.3 supports Python 2.7 (our organization has 2.7.8). We would like to use matplotlib as a plot tool. Is matplotlib 1.4.3 compatible to run on a Linux system with RedHat 5.10? Thank you. Amy Fort
Got my answer here: http://stackoverflow.com/questions/30301986/matplotlib-imshow-and-pixel-intensity On Sun, May 17, 2015 at 10:02 PM, Amit Saha <ami...@gm...> wrote: > Hi all, > > Just trying to understand how the value of the matrix fed to imshow() > function determines the intensity of the pixel in grey scale mode. > Consider the example code: > > import random > import matplotlib.pyplot as plt > import matplotlib.cm as cm > > def pixels(n=3): > pixel_data = [] > for _ in range(n): > row = [] > for _ in range(n): > row.append(random.randint(1, 10)) > pixel_data.append(row) > return pixel_data > > if __name__ == '__main__': > pixel_data = pixels() > print(pixel_data) > plt.imshow(pixel_data, origin='lower', cmap=cm.Greys_r) > plt.show() > > > The pixel_data here is the 3*3 "matrix": > [[7, 4, 6], [7, 7, 6], [4, 7, 9]] > > How does the values here determine what shade of grey I see in the image? > > Thank you in advance. > > Best, > Amit. > > > -- > http://echorand.me -- http://echorand.me