matplotlib-users Mailing List for matplotlib

What is the preferred method to do the equivalent of plot_date
with log scaling for the non-date values?
Thanks,
Alan Isaac

Colleagues,
I am trying to follow the http://matplotlib.sourceforge.net/users/pyplot_tutorial.html tutorial with little success. The very first import fails with either 64 or 32-bit python. Any hints I have missed?
$ python
Python 2.6.1 (r261:67515, Feb 11 2010, 00:51:29)
[GCC 4.2.1 (Apple Inc. build 5646)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import matplotlib.pyplot as plt
Traceback (most recent call last):
 File "<stdin>", line 1, in <module>
 File "/Library/Python/2.6/site-packages/matplotlib-0.99.1.1-py2.6-macosx-10.3-fat.egg/matplotlib/pyplot.py", line 6, in <module>
 from matplotlib.figure import Figure, figaspect
 File "/Library/Python/2.6/site-packages/matplotlib-0.99.1.1-py2.6-macosx-10.3-fat.egg/matplotlib/figure.py", line 16, in <module>
 import artist
 File "/Library/Python/2.6/site-packages/matplotlib-0.99.1.1-py2.6-macosx-10.3-fat.egg/matplotlib/artist.py", line 5, in <module>
 from transforms import Bbox, IdentityTransform, TransformedBbox, TransformedPath
 File "/Library/Python/2.6/site-packages/matplotlib-0.99.1.1-py2.6-macosx-10.3-fat.egg/matplotlib/transforms.py", line 34, in <module>
 from matplotlib._path import affine_transform
ImportError: /Library/Python/2.6/site-packages/matplotlib-0.99.1.1-py2.6-macosx-10.3-fat.egg/matplotlib/_path.so: no appropriate 64-bit architecture (see "man python" for running in 32-bit mode)
>>> exit()
$ defaults write com.apple.versioner.python Prefer-32-Bit -bool yes
$ python
Python 2.6.1 (r261:67515, Feb 11 2010, 00:51:29)
[GCC 4.2.1 (Apple Inc. build 5646)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import matplotlib.pyplot as plt
Bus error
$
Sincerely,
Vlad
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On Wed, May 12, 2010 at 5:58 AM, Yannick Copin
<yan...@la...> wrote:
> gs = gridspec.GridSpec(3, 3)
> ax1 = gs[0, :]
>
I'm inclined to leave the GridSpec as it is and I prefer to have a
separate class for this (if we go for it). My inclination is to modify
subplot2grid to return such an instance. e.g.,
grid = gridspec.subplot2grid((2,2))
ax1 = grid[0,:]
Regards,
-JJ

On Tue, May 11, 2010 at 1:38 PM, John Hunter <jd...@gm...> wrote:
> This looks sufficiently general and useful that we may simply want it
> to live in the main tree (not as a toolkit) and have subplot2grd
> helper functionality available directly from pyplot.
>
Okay.
I'll merge this into the main tree and commit.
Regards,
-JJ

Hi,
Jae-Joon Lee <lee.j.joon@...> writes:
> gridspec is a module that implements matplotlib’s Subplot slightly
> differently. Current matplotlib’s Subplot only allows a Subplot to
> occupy a single cell of the n x m grid. gridspec enables a Subplot to
> occupy multiple cells.
Very interesting indeed. If I may comment on the usability, I wish function
gridspec.subplot could become directly a method of Gridspec. The current example:
gs = gridspec.GridSpec(3, 3)
ax1 = gridspec.subplot(gs[0, :])
ax2 = gridspec.subplot(gs[1,:-1])
ax3 = gridspec.subplot(gs[1:, -1])
ax4 = gridspec.subplot(gs[-1,0])
ax5 = gridspec.subplot(gs[-1,-2])
could be written in a much simpler way then, such as:
gs = gridspec.GridSpec(3, 3)
ax1 = gs[0, :]
ax2 = gs[1,:-1]
ax3 = gs[1:, -1]
ax4 = gs[-1,0]
ax5 = gs[-1,-2]
I would LOVE it!
+1 for getting these functionnalities straight in matplotlib: subplot management
always take a decent part of my scripts...
Cheers,