matplotlib-users Mailing List for matplotlib

On 7/10/07, Edin Salkovic <edi...@gm...> wrote:
> On 7/10/07, John Hunter <jd...@gm...> wrote:
> > Hey Edin, if you get a minute, could you contribute a patch against
> > the faq in htdocs/faq.html.template explaining how to install the
> > bakoma fonts for svg viewers? Is this sufficiently difficult that it
> > merits a FAQ?
>
> It sure is easy to forget :)
>
> Attached is the patch to the FAQ. I don't have the htdocs dir checked
> out. John, can you apply the patch?
Thanks to Michael Droettboom fonts can now be embedded in the SVG file.
See:
http://www.nabble.com/Embedded-fonts-in-SVG-t4057222.html
http://comments.gmane.org/gmane.comp.python.matplotlib.devel/2944
I also updated the FAQ.
Index: faq.html.template
===================================================================
--- faq.html.template (revision 3500)
+++ faq.html.template (working copy)
@@ -977,6 +977,23 @@
 docs</a> for details.
 """ ),
+ ('SVG-BAKOMA-FONTS-MATHTEXT',
+ "My SVG viewer doesn't properly display special (TeX) characters
+ ('\sum', '\infty',etc.) generated by mathtext. Is this a bug?",
+ """
+You need to install the BaKoMa fonts (TrueType version of the Computer
+Modern fonts) on your system. The BaKoMa fonts come packaged with
+matplotlib. They are located in the
+"site-packages/matplotlib/mpl-data/fonts/ttf" dir (the cm*.ttf files).
+Installation of the fonts varies from OS to OS.
+
+Alternatively, as of r3498 (matplotlib > 0.90.1) you can set
+svg.embed_char_paths to True in your matplotlibrc file. This
+setting makes matplotlib embed all fonts as paths in the SVG file,
+which results in a "portable" SVG file, at the cost of bigger file
+size and uneditable text.
+""" ),
+
 ('LEAKS',
 'matplotlib appears to be leaking memory, what should I do?',
 """\

Mark Bakker wrote:
> Viraj and Jeff -
>
> Maybe one extension of Jeff's answer.
> The process works as long as x, y, and z are 2D arrays of the same 
> size and shape.
> Hence, x and y don't have to form a rectangular grid.
> I have used this feature regularly for conformal mapping.
> And it makes a lot of sense.
> The contour routine simply looks for intersections between x and y values.
> Then when it plots it uses the x and y values in the arrays.
> So when those are not a rectangular grid, it doesn't care.
> It's a cool feature.
> I can give an example if you want,
>
> Mark
>
> 
>
> Viraj Vajratkar wrote:
> > hey guys... i got it... u can use contour(x,y,z)... as in
> > x=load('urfile1.dat'), y=load('urfile2.dat), z=load('urfile3.dat
> > ').... and then type out the above.... for details about the
> > parameters x,y,z see... .
> > http://www.scilab.org/product/man-eng/graphics/contour.htm .... so
> > matplotlib CAN plot a contour from discrete points!!!.... ive
> tried it
> > and it works...
> Viraj: That only works because x and y describe a rectangular
> grid. If
> x and y described irregularly spaced points, you would need to
> grid the
> data first using one of the methods described on that Cookbook page.
>
> -Jeff
>
>
Mark: That is cool - didn't know it could do that. So I guess the 
proper answer is contour requires x and y to describe a *regular*, but 
not recessarily rectilinear, grid. I should have known, since there is 
an example in basemap (ccsm_popgrid.py) that illustrates this.
-Jeff
-- 
Jeffrey S. Whitaker Phone : (303)497-6313
NOAA/OAR/CDC R/PSD1 FAX : (303)497-6449
325 Broadway Boulder, CO, USA 80305-3328

I thought it was cool the first time I saw it.
Just try something simple
from pylab import *
x,y = meshgrid(linspace(-5,5,101),linspace(0,5,101))
h = y
z = x + complex(0,1)*y
znew = z**0.25 # Doing a simple conformal map
xnew = znew.real
ynew = znew.imag
contourf(xnew,ynew,h,linspace(0,5,10))
axis('scaled')
And you get nice contours in a pieslice-shaped domain with an angle of 45
degrees
Mark
From: "Scott Sinclair" <sin...@uk...>
>
> That is very cool, I hadn't thought of it!
>
> So what you're saying is that any transformation (a complex distortion) of
> a regular rectangular grid is fine. The fact that the grid's 'pixels' are
> four sided quadrilaterals satisfies this condition and the contour algorithm
> works...
>
> Cheers,
> Scott
>
> >>> "Mark Bakker" <ma...@gm...> 7/11/2007 11:36 >>>
> Viraj and Jeff -
>
> Maybe one extension of Jeff's answer.
> The process works as long as x, y, and z are 2D arrays of the same size
> and shape.
> Hence, x and y don't have to form a rectangular grid.
> I have used this feature regularly for conformal mapping.
> And it makes a lot of sense.
> The contour routine simply looks for intersections between x and y values.
> Then when it plots it uses the x and y values in the arrays.
> So when those are not a rectangular grid, it doesn't care.
> It's a cool feature.
> I can give an example if you want,
>
> Mark
>

That is very cool, I hadn't thought of it!
=20
So what you're saying is that any transformation (a complex distortion) of =
a regular rectangular grid is fine. The fact that the grid's 'pixels' are =
four sided quadrilaterals satisfies this condition and the contour =
algorithm works...
=20
Cheers,
Scott
>>> "Mark Bakker" <ma...@gm...> 7/11/2007 11:36 >>>
Viraj and Jeff -
Maybe one extension of Jeff's answer.
The process works as long as x, y, and z are 2D arrays of the same size =
and shape.
Hence, x and y don't have to form a rectangular grid.=20
I have used this feature regularly for conformal mapping.=20
And it makes a lot of sense.=20
The contour routine simply looks for intersections between x and y values.
Then when it plots it uses the x and y values in the arrays.=20
So when those are not a rectangular grid, it doesn't care.
It's a cool feature.
I can give an example if you want,
Mark
=20
Viraj Vajratkar wrote:
> hey guys... i got it... u can use contour(x,y,z)... as in
> x=3Dload('urfile1.dat'), y=3Dload('urfile2.dat), z=3Dload('urfile3.dat
> ').... and then type out the above.... for details about the=20
> parameters x,y,z see... .
> http://www.scilab.org/product/man-eng/graphics/contour.htm .... so
> matplotlib CAN plot a contour from discrete points!!!.... ive tried =
it=20
> and it works...
Viraj: That only works because x and y describe a rectangular grid. If
x and y described irregularly spaced points, you would need to grid the
data first using one of the methods described on that Cookbook page.=20
-Jeff
Please find our Email Disclaimer here: http://www.ukzn.ac.za/disclaimer/

Viraj and Jeff -
Maybe one extension of Jeff's answer.
The process works as long as x, y, and z are 2D arrays of the same size and
shape.
Hence, x and y don't have to form a rectangular grid.
I have used this feature regularly for conformal mapping.
And it makes a lot of sense.
The contour routine simply looks for intersections between x and y values.
Then when it plots it uses the x and y values in the arrays.
So when those are not a rectangular grid, it doesn't care.
It's a cool feature.
I can give an example if you want,
Mark
Viraj Vajratkar wrote:
> > hey guys... i got it... u can use contour(x,y,z)... as in
> > x=load('urfile1.dat'), y=load('urfile2.dat), z=load('urfile3.dat
> > ').... and then type out the above.... for details about the
> > parameters x,y,z see... .
> > http://www.scilab.org/product/man-eng/graphics/contour.htm .... so
> > matplotlib CAN plot a contour from discrete points!!!.... ive tried it
> > and it works...
> Viraj: That only works because x and y describe a rectangular grid. If
> x and y described irregularly spaced points, you would need to grid the
> data first using one of the methods described on that Cookbook page.
>
> -Jeff
>