matplotlib-users Mailing List for matplotlib (Page 7)

Great, thank you very much...that did the trick.
I don't know why broken_barh does not come in the legend, either; maybe is
because of the ambiguity as to which color to use in the legend...a single
broken barh command can have several bars with different colors. 
gsal
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[Forgot to reply-all, sorry for the dup, gsal]
On Fri, Jan 4, 2013 at 1:22 PM, gsal <sal...@gm...> wrote:
> can you provide an example? The reference help is only two lines!
>
> Given:
> [code]
> import numpy as np
> import matplotlib.pyplot as plt
>
> fig = plt.figure()
> ax = fig.add_subplot(111)
> ax.broken_barh([ (110, 30), (150, 10) ] , (10, 9), facecolors='b',
> label='barh')
>
> ax.set_xlim((0,200))
> ax.set_ylim((0,50))
>
> ax.legend()
>
> plt.show()
> [/code]
>
> How do I import what in order to, say, create a plot
> "plot([0.0],[0.0],'bs')" so that I can at least plot a marker of the same
> color as my broken_barh so that when the legend is added, the correct icon
> precedes the label?
>
> I tried adding
>
> pp = plt.plot([80],[40],'bs', label='proxy artist')
>
> to the previous program, right before the legend command, but it actually
> plots the marker, too.
>
> Is there a way to import "plot" or "Line2D" or something so that I can
> produce an artist that is NOT related to the plot and, hence, not plotted?
> (is that what "proxy artist" means?).
>
Yes. Proxy artists are created in memory but never added to the axes
object. Here's an expanded version of the example:
import matplotlib.patches as mpatch
import matplotlib.pyplot as plt
fig, ax = plt.subplots()
patch = mpatch.Rectangle((0, 0), 1, 1, fc="r")
ax.legend([patch], ["Proxy artist"])
plt.show()
So for your example, I'd do the following:
import numpy as np
import matplotlib.pyplot as plt
import matplotlib.patches as mpatch
fig = plt.figure()
ax = fig.add_subplot(111)
ax.broken_barh([ (110, 30), (150, 10) ] , (10, 9), facecolors='b',
label='barh')
ax.set_xlim((0,200))
ax.set_ylim((0,50))
fakeredbar = mpatch.Rectangle((0, 0), 1, 1, fc="r")
fakebluebar = mpatch.Rectangle((0, 0), 1, 1, fc="b")
ax.legend([fakeredbar, fakebluebar], ['Red Data', 'Blue Data'])
plt.show()
Now to me, it seems very strange that broken_barh doesn't generate any
items in a legend. Not sure why that is but it seems like a bug.
Hope that helps,
-paul

can you provide an example? The reference help is only two lines! 
Given:
[code]
import numpy as np
import matplotlib.pyplot as plt
fig = plt.figure()
ax = fig.add_subplot(111)
ax.broken_barh([ (110, 30), (150, 10) ] , (10, 9), facecolors='b',
label='barh')
ax.set_xlim((0,200))
ax.set_ylim((0,50))
ax.legend()
plt.show()
[/code]
How do I import what in order to, say, create a plot
"plot([0.0],[0.0],'bs')" so that I can at least plot a marker of the same
color as my broken_barh so that when the legend is added, the correct icon
precedes the label?
I tried adding 
pp = plt.plot([80],[40],'bs', label='proxy artist')
to the previous program, right before the legend command, but it actually
plots the marker, too.
Is there a way to import "plot" or "Line2D" or something so that I can
produce an artist that is NOT related to the plot and, hence, not plotted?
(is that what "proxy artist" means?).
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On Fri, Jan 4, 2013 at 8:41 AM, gsal <sal...@gm...> wrote:
> So, it looks like broken_barh's do not show up on the legend...is there
> work
> around for this?
>
> Or,
>
> Is there a way to fake a legend? A way to set legend to whatever I want?
>
> Thanks,
>
> gsal
>
>
To fake a legend, try using so-called proxy artists:
http://matplotlib.org/users/legend_guide.html#using-proxy-artist
-paul

Maybe you can use the zoom example
<http://matplotlib.org/examples/pylab_examples/axes_zoom_effect.html> and
the binding method idea so that when you click on some point in the main
graph, the zooming graph updates and plots from -50 to +50 days from the
point that you clicked on the main graph...just an idea.
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Hhhmmm...I am thinking to may have to implement some interactivity
(callbacks) to your plot and be able to, say, click or right click and
demand that the current settings be stored or restored from choices
previously stored...but this has to be all your doing.
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So, it looks like broken_barh's do not show up on the legend...is there work
around for this?
Or,
Is there a way to fake a legend? A way to set legend to whatever I want? 
Thanks,
gsal
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Alex Goodman <goo...@il...>
writes:
> Try using the set_ylabel() and set_xlabel() methods for each Axes instance
> instead, eg:
>
> a[0].set_ylabel('f1')
> ...
works as intended, tx Alex

Hi Giacomo,
Try using the set_ylabel() and set_xlabel() methods for each Axes instance
instead, eg:
a[0].set_ylabel('f1')
a[0].set_xlabel('t')
a[1].set_ylabel('f2')
a[1].set_xlabel('t')
On Fri, Jan 4, 2013 at 5:44 AM, <gia...@po...> wrote:
> two plots in a figure:
> ########################################################################
> from pylab import *
> ...
> f,a = subplots(nrows=2, sharex=False, sharey=False)
> a[0].plot(x,f0(x))
> ylabel('f1')
> xlabel('t')
> ...
> a[1].plot(x,f1(x))
> ylabel('f2')
> xlabel('t')
> ...
> show()
> ########################################################################
> but all i can get are labels for ONLY the lower subplot, what shoud I do?
>
> any help will be appreciated
>
> tia
> gb
>
>
>
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Alex Goodman
University of Illinois at Urbana-Champaign
Email: goo...@il...

two plots in a figure:
########################################################################
from pylab import *
...
f,a = subplots(nrows=2, sharex=False, sharey=False)
a[0].plot(x,f0(x))
ylabel('f1')
xlabel('t')
...
a[1].plot(x,f1(x))
ylabel('f2')
xlabel('t')
...
show()
########################################################################
but all i can get are labels for ONLY the lower subplot, what shoud I do?
any help will be appreciated
tia
 gb

Thank you everyone for your answers. My legend is no longer defaced since
I de-faced the call to scatter() :-)

Joe,
I think the problem is the edgecolor='face' in the scatter call for the
open circles. For me when I omit that, it all works. I'd also note
that calling legend after draw results in the legend showing the circles
correctly colored.
Regards,
Jon
On Wed, 2013年01月02日 at 16:46 -0800, Joe Louderback wrote:
> Using matplotlib.pyplot I create a scatter plot using two symbols, an
> open circle, and a filled circle. The legend for this plot shows both
> labels, but there is no symbol for the open circles (see
> missing_legend_circles.png). Switching to matplotlib.pylab yields the
> same result. However, from an "ipython --pylab" session the open
> circles are displayed in the legend. This has me more baffled than
> usual. Here's the code to reproduce the enclosed figure:
> 
> import matplotlib.pyplot as plt
> 
> 
> fig = plt.figure()
> plot = fig.add_subplot(111)
> 
> 
> plot.scatter([1, 2, 3], [4, 5, 6], c = [0.2, 0.4, 0.6], label =
> 'one', 
> cmap = 'jet', marker = 'o', edgecolor = 'face') 
> 
> 
> plot.scatter([1, 2, 3], [7, 6, 5], c = [0.2, 0.4, 0.6], label = 'two',
> cmap = 'jet', marker = 'o', edgecolor = 'face', 
> facecolor = 'none')
> plot.legend()
> plt.show()
> 
> 
> 
> 
> This is with matplotlib 1.1 and 1.2 on Windows 7 with the TkAgg, WxAgg
> and WX backends.
> 
> 
> Thank you for any help.
> 
> 
> -- Joe Louderback
-- 
______________________________________________________________
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js...@cf... 60 Garden Street, MS 83
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I doubt there is a color called 'face', according to documentation:
In [2]: setp(mat.collections.PathCollection,'edgecolor')
 edgecolor: matplotlib color arg or sequence of rgba tuples 
probably because matplotlib doesn't know how rend the color 'face'?
Chao
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On Wed, Jan 2, 2013 at 4:46 PM, Joe Louderback <jgl...@gm...>wrote:
> import matplotlib.pyplot as plt
>
> fig = plt.figure()
> plot = fig.add_subplot(111)
>
> plot.scatter([1, 2, 3], [4, 5, 6], c = [0.2, 0.4, 0.6], label = 'one',
> cmap = 'jet', marker = 'o', edgecolor = 'face')
>
> plot.scatter([1, 2, 3], [7, 6, 5], c = [0.2, 0.4, 0.6], label = 'two',
> cmap = 'jet', marker = 'o', edgecolor = 'face',
> facecolor = 'none')
> plot.legend()
> plt.show()
>
I'm not quite sure what /should/ happen when you set the `facecolor` to
'none' and the `edgecolor` to 'face'. I'm surprised anything shows up at
the axes at all. But if you remove the `edgecolor` kwarg things look better:
import matplotlib.pyplot as plt
fig = plt.figure()
plot = fig.add_subplot(111)
plot.scatter([1, 2, 3], [4, 5, 6], c = [0.2, 0.4, 0.6], label = 'one',
 cmap = 'jet', marker = 'o', edgecolor = 'face')
plot.scatter([1, 2, 3], [7, 6, 5], c = [0.2, 0.4, 0.6], label = 'two',
 cmap = 'jet', marker = 'o', facecolor='none')
plot.legend()
plt.show()

Using matplotlib.pyplot I create a scatter plot using two symbols, an open
circle, and a filled circle. The legend for this plot shows both labels,
but there is no symbol for the open circles (see
missing_legend_circles.png). Switching to matplotlib.pylab yields the same
result. However, from an "ipython --pylab" session the open circles are
displayed in the legend. This has me more baffled than usual. Here's the
code to reproduce the enclosed figure:
import matplotlib.pyplot as plt
fig = plt.figure()
plot = fig.add_subplot(111)
plot.scatter([1, 2, 3], [4, 5, 6], c = [0.2, 0.4, 0.6], label = 'one',
 cmap = 'jet', marker = 'o', edgecolor = 'face')
plot.scatter([1, 2, 3], [7, 6, 5], c = [0.2, 0.4, 0.6], label = 'two',
 cmap = 'jet', marker = 'o', edgecolor = 'face',
 facecolor = 'none')
plot.legend()
plt.show()
This is with matplotlib 1.1 and 1.2 on Windows 7 with the TkAgg, WxAgg and
WX backends.
Thank you for any help.
-- Joe Louderback

I think using the profiler is the best bet here. We've used that in the 
past to track down things that take a long time to import quite 
successfully. I'm not seeing any slowness here, so that is likely do to 
an environmental difference on your machine, implying you'll really need 
to run the profiler yourself. I recommend runsnakerun to examine the 
profile output -- if you have trouble interpreting it, feel free to send 
me your raw profiler data to me off list.
Mike
On 12/31/2012 02:21 PM, C M wrote:
> Resurrecting an old thread here....
>
> On Tue, Mar 29, 2011 at 3:23 PM, David Kremer <da...@da... 
> <mailto:da...@da...>> wrote:
>
> > I would recommend running the import in the Python profiler to
> determine
> > where most of the time is going. When I investigated this a few
> years
> > back, it was mainly due to loading the GUI toolkits, which are
> > understandably quite large. You can avoid most of that by using
> the Agg
> > backend. If you're using the Agg backend and still experiencing
> > slowness, it may be that load-up issues have crept back into
> matplotlib
> > since then -- but we need profiling data to figure out where and
> how.
>
>
> Importing Matplotlib is very slow for me, too. For a wxPython 
> application with embedded Matplotlib, I am getting "load" times of > 
> 20 seconds when "cold" importing matplotlib, with this (circa mid 
> 2004) computer setup: Windows XP, sp3, Intel Pentium, 1.70 Ghz, 1 GB 
> RAM.
>
> This is, by the way, an import well after Python and wxPython have 
> already been loaded into RAM, as it happens by a user action, so none 
> of the time involved here is due to loading Python or wxPython (they 
> both load more quickly--about 10 seconds to cold import them, my code, 
> images, and some other libraries).
>
> First of all: does that amount of time seem appropriate for that fast 
> of a system--or is that too long? It definitely *feels* way too long 
> from a user perspective (for comparison Word or PowerPoint loads on 
> this computer in about 2.5 seconds).
>
> Trying to improve it and following this old thread, I have switched to
>
> matplotlib.use('Agg')
>
> instead of
>
> matplotlib.use('wxAgg')
>
> as suggested to speed things up...but it is no faster.
>
> I see, though, that I also have lines such as:
>
> from matplotlib.backends.backend_wxagg import FigureCanvasWxAgg
> from matplotlib.backends.backend_wxagg import NavigationToolbar2WxAgg
>
> Would the presence of these imports obviate the fact that I switched 
> to using the Agg instead of the wxAgg? If so, is there any way to use 
> something faster here (I suspect not but thought I'd ask).
>
> Also, what else should I consider doing to reduce the import time 
> significantly? (I have to learn how to use the profiler, so I haven't 
> done that yet).
>
> Thanks,
> Che
>
> >
> > Mike
>
> Thank you a lot for your answer.
>
> I noticed than _matplotlib.pyplot_ is longer to be imported the
> first time than
> if it has already been imported previously (maybe things are
> already loaded in
> ram memory), and we don't need to fetch it from the hard drive
> thanks to the
> kernel.
>
> As far I see, the function calls are the same for the two logs I
> obtained,
> except than the first took 6s instead of 1.4s.
>
>
>
>
> The two logs have been obtained using :
> <code>
> python -m cProfile temp.py
> </code>
>
> where temp.py consist of two lines :
>
> <code>
> #!/usr/bin/env python2
>
> import matplotlib.pyplot
> </code>
>
>
>
>
>
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Hi,
I was wondering if anyone had the zip file from John's Advanced matplotlib
tutorial <http://www.youtube.com/watch?v=DNRJwENqEUY> ?
The referenced bit.ly URL in the video no longer works.
Thanks!
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On Tuesday, January 1, 2013, Alejandro Weinstein wrote:
> Hi:
>
> When I run the simple_3danim.py example
> (http://matplotlib.org/examples/animation/simple_3danim.html) I get
> the following error:
>
> File "simple_3danim.py", line 47, in <module>
> ax.set_xlim3d([0.0, 1.0])
> File
> "/usr/local/lib/python2.7/dist-packages/matplotlib-1.3.x-py2.7-linux-x86_64.egg/mpl_toolkits/mplot3d/axes3d.py",
> line 571, in set_xlim3d
> if right is None and iterable(left):
> NameError: global name 'iterable' is not defined
>
> I can fix this by replacing `ax.set_xlim3d([0.0, 1.0])` by
> `ax.set_xlim3d(0.0, 1.0)` (and similarly for the `ax.set_ylim3d` and
> `ax.set_zlim3d`).
>
> I'm running mpl ver. 1.3.
>
> If this is a bug, I can send a PR.
>
> Alejandro.
Alejandro,
Yes, it is a bug, but in axes3d, not the example (both calls should be
legit). A PR has already been submitted to the 1.2.x branch and will be
merged to master soon.
Ben Root

Hi:
When I run the simple_3danim.py example
(http://matplotlib.org/examples/animation/simple_3danim.html) I get
the following error:
 File "simple_3danim.py", line 47, in <module>
 ax.set_xlim3d([0.0, 1.0])
 File "/usr/local/lib/python2.7/dist-packages/matplotlib-1.3.x-py2.7-linux-x86_64.egg/mpl_toolkits/mplot3d/axes3d.py",
line 571, in set_xlim3d
 if right is None and iterable(left):
NameError: global name 'iterable' is not defined
I can fix this by replacing `ax.set_xlim3d([0.0, 1.0])` by
`ax.set_xlim3d(0.0, 1.0)` (and similarly for the `ax.set_ylim3d` and
`ax.set_zlim3d`).
I'm running mpl ver. 1.3.
If this is a bug, I can send a PR.
Alejandro.

No, I didn't... I believe that in this specific case, I just manually drew
a decently sized box around the axis spine and implemented my own contains
method to match.
It would be nice for every artist to be consistent in this area though.
Maybe a MEP is in order to make every artist have a consistent interface as
defined by the base class?
 On Dec 30, 2012 1:00 AM, "Michael McNeil Forbes" <
mic...@gm...> wrote:
> On 7 Oct 2011, at 4:56 PM, Daniel Hyams wrote:
>
> I'm wanting to highlight the artist under the cursor with a transparent
>> Rectangle patch. To do this, I have very, roughly, in a mouse motion
>> handler,
>>
>> under = self.figure.hitlist(ev)
>> if under:
>> artist = under[0]
>> bbox = artist.get_window_extent()
>> highlight = matplotlib.patches.Rectangle(**
>> xy=bbox.min,width=bbox.width,**height=bbox.height,alpha=0.2,**
>> color='yellow')
>> # further code to blit the last captured graph region with highlight
>> drawn on top
>>
>> The main problem is that all artists don't implement get_window_extent();
>> a Text object does, and a legend object does, but the Axis objects do not.
>>
>> So is there a general way to get the bounding box of an artist?
>>
>
> Did you ever find a way to get the bounding box of an artist? I could use
> this too.
>
> Michael.
>