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Showing 3 results of 3

From: Eric F. <ef...@ha...> - 2008年05月03日 18:08:13
Manuel Metz wrote:
> Hi,
> while adding the step-histogram I learned about the change of 
> numpy.histogram. As MPL trunk relies in numpy 1.1, I think its a good 
> idea to switch to the new histogram, i.e. use "new=True". Indeed, this 
> is required to be able to allow to give bin-edges, which is possible 
> with MPL 0.91.
> However, while keeping API compatibility on the one hand by allowing 
> to provide bin-edges, this step also breaks API compatibility since the 
> definition of bins has changed:
> 
> numpy 1.0.4
> 
> In [1]:from numpy import *
> In [2]:random.seed(18)
> In [3]:x = random.random(100)
> In [4]:histogram(x, bins=array([0,0.1,0.2]))
> Out[4]:(array([11, 11, 78]), array([ 0. , 0.1, 0.2]))
> 
> numpy 1.1.0.dev5106'
> 
> In [1]:from numpy import *
> In [2]:random.seed(18)
> In [3]:x = random.random(100)
> In [4]: histogram(x, bins=array([0,0.1,0.2]),new=True)
> Out[4]: (array([11, 11]), array([ 0. , 0.1, 0.2]))
> 
> 
> How should this be handled? Follow numpy, breaking API compatibility and 
> point to the API change of histogram? Or keeping API compatibility with 
> MPL0.91 and write a wrapper function?
> 
> I would prefer the first option...
I strongly agree.
Eric
> 
> Manuel
From: Manuel M. <mm...@as...> - 2008年05月03日 16:57:39
Here's the link to the numpy wiki:
http://projects.scipy.org/scipy/numpy/roadmap#Semanticchangeforhistogram
Manuel Metz wrote:
> Hi,
> while adding the step-histogram I learned about the change of 
> numpy.histogram. As MPL trunk relies in numpy 1.1, I think its a good 
> idea to switch to the new histogram, i.e. use "new=True". Indeed, this 
> is required to be able to allow to give bin-edges, which is possible 
> with MPL 0.91.
> However, while keeping API compatibility on the one hand by allowing 
> to provide bin-edges, this step also breaks API compatibility since the 
> definition of bins has changed:
> 
> numpy 1.0.4
> 
> In [1]:from numpy import *
> In [2]:random.seed(18)
> In [3]:x = random.random(100)
> In [4]:histogram(x, bins=array([0,0.1,0.2]))
> Out[4]:(array([11, 11, 78]), array([ 0. , 0.1, 0.2]))
> 
> numpy 1.1.0.dev5106'
> 
> In [1]:from numpy import *
> In [2]:random.seed(18)
> In [3]:x = random.random(100)
> In [4]: histogram(x, bins=array([0,0.1,0.2]),new=True)
> Out[4]: (array([11, 11]), array([ 0. , 0.1, 0.2]))
> 
> 
> How should this be handled? Follow numpy, breaking API compatibility and 
> point to the API change of histogram? Or keeping API compatibility with 
> MPL0.91 and write a wrapper function?
> 
> I would prefer the first option...
> 
> Manuel
> 
From: Manuel M. <mm...@as...> - 2008年05月03日 16:35:46
Hi,
 while adding the step-histogram I learned about the change of 
numpy.histogram. As MPL trunk relies in numpy 1.1, I think its a good 
idea to switch to the new histogram, i.e. use "new=True". Indeed, this 
is required to be able to allow to give bin-edges, which is possible 
with MPL 0.91.
 However, while keeping API compatibility on the one hand by allowing 
to provide bin-edges, this step also breaks API compatibility since the 
definition of bins has changed:
numpy 1.0.4
In [1]:from numpy import *
In [2]:random.seed(18)
In [3]:x = random.random(100)
In [4]:histogram(x, bins=array([0,0.1,0.2]))
Out[4]:(array([11, 11, 78]), array([ 0. , 0.1, 0.2]))
numpy 1.1.0.dev5106'
In [1]:from numpy import *
In [2]:random.seed(18)
In [3]:x = random.random(100)
In [4]: histogram(x, bins=array([0,0.1,0.2]),new=True)
Out[4]: (array([11, 11]), array([ 0. , 0.1, 0.2]))
How should this be handled? Follow numpy, breaking API compatibility and 
point to the API change of histogram? Or keeping API compatibility with 
MPL0.91 and write a wrapper function?
I would prefer the first option...
Manuel

Showing 3 results of 3

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